Y^2+4y=-8
add 8 both sides
y^2+4y+8=0 in the form of ax²+bx+c=0
Factor it
by formula
-b+-(√b²-4ac)/2a
-4+-(√16-32)/2*1
-4+-(√-16)/2
-4+-4i/2
-2+-2i where√-1=i

4 0

3 years ago

Correct

Gekata [30.6K]

Answer:

Step-by-step explanation:

$\frac{3 }{27} \frac{miles}{minutes}$ * $\frac{60}{1} \frac{min}{hour}$ * $\frac{1}{.6213} \frac{km}{mile}$

4km ÷ 10.73 km/hr = .37 hr = 22.3 minutes

7 0

3 years ago

1. Thom has a scale model of his car. The

MariettaO [177]

$x =\frac{4}{3}inch$ is the size in wheels on the scale model .

<u>Step-by-step explanation:</u>

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ $\frac{1}{12} = \frac{x}{16}$ { x is size of wheel in scale model }

⇒ $\frac{1(16)}{12} = \frac{x}{16}(16)$

⇒ $x =\frac{16}{12}$

⇒ $x =\frac{4}{3}inch$

Therefore , $x =\frac{4}{3}inch$ is the size in wheels on the scale model .

5 0

4 years ago