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kirill115 [55]
2 years ago
11

I will give brainiest answer to whomever solves this

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
5 0

Let the numbers be x = 5x+18

3(5x+18) + 4x= 16

15x+ 54+ 4x= 16

19x = 16-54

X=-38/19

X= -2

5x+18= 5 × -2+18 = 8

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A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

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3 years ago
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17.24

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17.24 rounded to ones = 18.00

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