Here,
y=mx+c
the slope of the line 6x+4y= -16 is -20.
if the two lines are perpendicular, the slope of 1st line * slope of second line=-1
the slope of the 2nd line is -1/2
y-y1=m(x-x1)
y-13=-1/2(x- -18)
when you solve, you get the equation of the line as 2y+x=50
In basic geometry, if two geometry objects intersect at right angles (90 degrees or π / 2 radians), they are vertical.
If two lines intersect at right angles, the line is perpendicular to another line. Explicitly (1) if two lines intersect, the first line is perpendicular to the second line. (2) At the intersection, the straight line angle on one side of the first line is cut by the second line into two congruent angles. Verticality can be shown as symmetric. That is, if the first line is perpendicular to the second line, then the second line is also perpendicular to the first line. Therefore, two straight lines can be said to be perpendicular (to each other) without specifying the order.
Learn more about Perpendicular here: brainly.com/question/7098341
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Step-by-step explanation:
First,
(A intersect B) = {1,2,4,5} intersect {1,3,5,7}
= {1,5}
Now,
A'n B = (A) - (A intersect B)
= {1,2,4,5} - {1,5}
= {2,4}
Well a difference is the difference between them. difference means subtraction. So so a difference can be written as:
40.67 - (-41.29)
If you subtract a negative number you really add it. to make sense of this you could say 40.67 is 40.67 units away from zero in the positive direction. whereas -41.29 is 41.29 units away in the negative direction. since they go in opposite directions away from zero that means that thw length between them is extended and must then be added together. So
40.67 + 41.29 = 81.96
Answer:
Step-by-step explanation:
We assume you want to compare your expression to the form ...
a(x -h)² +k
1/2(x +1)² +k
The multiplier outside parentheses is ...
a = 1/2
The horizontal offset inside parentheses is ...
-h = 1
h = -1
The vertical offset outside parentheses is ...
k = -3
This DE has characteristic equation

with a repeated root at r = 3/2. Then the characteristic solution is

which has derivative

Use the given initial conditions to solve for the constants:


and so the particular solution to the IVP is
