D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:

<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E

therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
Answer:
Read the explanation down
Step-by-step explanation:
This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y−y1=m(x−x1).
Isolate y by first adding 6x to each side:
9y=6x−18
Divide each side by 9:
y=23x−2
Now graph the line y=23x−2 by first plotting the y intercept at (0,−2), then connecting points with a slope of 23.
graph{2/3x-2 [-10, 10, -5, 5]}
Answer:
- (3, 5), (1, 2) and (5, 1)
Step-by-step explanation:
Make three systems with pairs of lines and solve them to work out the vertices.
1) <u>Line 1 and line 2</u>
<u>Double the second equation and subtract equations:</u>
- -3x + 2y - 2(2x + y) = 1 - 2(11)
- -3x - 4x = 1 - 22
- -7x = - 21
- x = 3
<u>Find y:</u>
- 2*3 + y = 11
- 6 + y = 11
- y = 11 - 6
- y = 5
The point is (3, 5)
2) <u>Line 1 and line 3</u>
<u>Triple the second equation and add up equations:</u>
- -3x + 2y + 3(x + 4y) = 1 + 3(9)
- 2y + 12y = 1 + 27
- 14y = 28
- y = 2
<u>Find x:</u>
- x + 4*2 = 9
- x + 8 = 9
- x = 1
The point is (1, 2)
3) <u>Line 2 and line 3</u>
<u>Double the second equation and subtract the equations:</u>
- 2x + y - 2(x + 4y) = 11 - 2(9)
- y - 8y = 11 - 18
- - 7y = - 7
- y = 1
<u>Find x:</u>
- x + 4*1 = 9
- x + 4 = 9
- x = 5
The point is (5, 1)
Answer:
The center is [-1,-2
Step-by-step explanation: