Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
-3: y = -2 * (-3) - 7 = 6 - 7 = -1
0: y = -2 * 0 - 7 = -7
3: y = -2 * 3 - 7 = -6 - 7 = -13
6: y = -2 * 6 - 7 = -12 - 7 = =-19
C i thinks, but im not even sure so
A=4-3b
subtract 4 from both sides
a-4=-3b
divide by -3 for both sides
(a-4)/-3 = b
You would set the equations equal to eachother and get x=-5/4 and then plug that in for x, i hope this helps!
