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katrin2010 [14]
2 years ago
7

The time it takes to clean up after an anniversary party varies inversely as the number of people cleaning. If 3 people work tog

ether to clean, it will take them 90 minutes. How long will it take if the number of people cleaning is increased to 5?
Mathematics
2 answers:
notsponge [240]2 years ago
7 0

Answer: 54 minutes

Step-by-step explanation:

Norma-Jean [14]2 years ago
3 0

Answer:

54minutes

Step-by-step explanation:

Let the time taken to clean up be t

Let the number of people cleaning be n

If the time it takes to clean up after an anniversary party varies inversely as the number of people cleaning then;

t = k/n

k is the constant of proportionality

If 3 people work together to clean, and took them 90 minutes, this means

at t = 90, n=3

Substitute

90 = k/3

k = 3×90

k = 270

To et the time it will take 5people to clean, the will say;

t =k/n

t =270/5

t = 54 minutes

Hence it will take 5 people 54minues to clean

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Consider the following frequency distribution.
Zarrin [17]

Answer:

Class interval                            10-19 20-29 30-39 40-49 50-59

cumulative frequency               10      24       41        48       50

cumulative relative frequency 0.2   0.48     0.82    0.96      1

Step-by-step explanation:

1.

We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.

Cumulative frequency

10

10+14=24

14+17=41

41+7=48

48+2=50

sum of frequencies is 50 so the relative frequency is f/50.

Relative frequency

10/50=0.2

14/50=0.28

17/50=0.34

7/50=0.14

2/50=0.04

Cumulative relative frequency

0.2

0.2+0.28=0.48

0.48+0.34=0.82

0.82+0.14=0.96

0.96+0.04=1

The cumulative relative frequency is calculated using relative frequency.

Relative frequency is calculated by dividing the respective frequency to the sum of frequency.

The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.

The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.

4 0
3 years ago
Convert 1 /20 into a decimal and then into a percentage
DerKrebs [107]

Answer:

Decimal 1/20= .05

Percent 1/20= 5%

Step-by-step explanation:

7 0
3 years ago
A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a
Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

                                   p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

p^4 (1-p)

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

                                    p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

7 0
3 years ago
a. 0.98 – 0.053 b. 0.67 – 0.4 c. 0.3 – 0.002 d. 3.2 – .789 e. 6.53 – 4.298 f. 6 – 4.32 g. 7 – 3.574 h. 4.83 – 1.8 i. 3.7 – 1.8 j
Pavlova-9 [17]

a. 0.927

We have:

0.98 – 0.053

We can re-write it as:

0. 9 8 0 -

0. 0 5 3

Moving digits to the right:

0. 9 7 10 -

0. 0 5 3

Digit-per-digit subtraction:

0. 9 2 7


b. 0.27

We have:

0.67 – 0.4

We can re-write it as:

0. 6 7 -

0. 4 0

Digit-per-digit subtraction:

0. 2 7


c. 0.298

We have:

0.3 – 0.002

We can re-write it as:

0. 3 0 0 -

0. 0 0 2

Moving digits to the right:

0. 2 10 0 -

0. 0 0 2

Again:

0. 2 9 10 -

0. 0 0 2

Digit-per-digit subtraction:

0. 2 9 8


d. 2.411

We have:

3.2 – .789

We can re-write it as:

3. 2 0 0 -

0. 7 8 9

We need to rewrite the first term by moving digits to the right several times:

3. 2 0 0 = 2. 12 0 0 = 2. 11 10 0 = 2. 11 9 10

So now we have:

2. 11 9 10 -

0. 7 8 9

Digit-per-digit subtraction:

2. 4 1 1


e. 2.232

We have:

6.53 – 4.298

We can re-write it as:

6. 5 3 0 -

4. 2 9 8

We need to rewrite the first term by moving digits to the right several times:

6. 5 3 0 = 6. 5 2 10 = 6. 4 12 10

So now we have:

6. 4 12 10 -

4. 2 9 8

Digit-per-digit subtraction:

2. 2 3 2


f. 1.68

We have:

6 – 4.32

We can re-write it as:

6. 0 0 -

4. 3 2

We need to rewrite the first term by moving digits to the right several times:

6. 0 0 = 5. 10 0 = 5. 9 10

So now we have:

5. 9 10 -

4. 3 2

Digit-per-digit subtraction:

1. 6 8


g. 4.426

We have:

7 – 3.574

We can re-write it as:

7. 0 0 0 -

3. 5 7 4

We need to rewrite the first term by moving digits to the right several times:

7. 0 0 0 = 6. 10 0 0 = 6. 9 10 0 = 6. 9 9 10

So now we have:

6. 9 9 10 -

3. 5 7 4 =

Digit-per-digit subtraction:

3. 4 2 6


h. 3.03

We have:

4.83 – 1.8

We can re-write it as:

4. 8 3 -

1. 8 0

We can immediately do the digit-per-digit subtraction:

3. 0 3


i. 2.9

We have:

3.7 – 1.8

We can re-write it as:

3. 7 -

1. 8

We need to rewrite the first term by moving digits to the right:

3. 7 = 2. 17

So now we have:

2. 17 -

1. 8 =

Digit-per-digit subtraction:

2. 9


j. 4.538

We have:

16.17 – 11.632

We can re-write it as:

1 6 . 1 7 0 -

1 1 . 6 3 2

We need to rewrite the first term by moving digits to the right:

1 6. 1 7 0 = 1 6. 1 6 10 = 1 5. 11 6 10  

So now we have:

1 5. 11 6 10 -

1 1. 6 3 2 =

Digit-per-digit subtraction:

0 4. 5 3 8

3 0
3 years ago
Aurora is moving to a new house she has lived in her current house for 6 years how many months is that how many day
marishachu [46]
(6x12=) 72 months,
(6x365=) 2,190 days
7 0
3 years ago
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