Answer:
See step by step explanation
Step-by-step explanation:
Sample size n = 800
p₁ = 71 % p₁ = 0,71 and q₁ = 0,29
Claim from political strategy wants evaluation to see if that sample implies that residents who favor the construction are more than 68 %
Then
p₀ = 68% p₀ = 0,68
Sample size 800 big enough to use the approximation of binomial distribution to normal distribution
1) Hypothesis Test
Null Hypothesis H₀ p₁ = p₀
Alternative Hypothesis Hₐ p₁ > p₀
2)Test Statistics z (s)
z(s) = ( p₁ - p₀ ) / √p₁*q₁/n
z(s) = 0,03 / √0,71*0,29/800
z(s) = 0,03 / 0,016
z(s) = 1,875
3) In the problem statement the expression " more than " has to be formulated in the alternative hypothesis and indicates that the test is one tail test to the right
4) z(s) = 1.875 from z-Table we get p-value = 0,030
Now significance level is α = 0,02
Therefore p-value > 0.02
Then that value corresponds to the acceptance region for H₀.
We don´t have enough evidence to support the strategist´s claim
5) The level of significance is α = 0,02
6) If now we change α to be equal to 0,01 α = 0,01
p-value > 0,01 and still we have to accept H₀
7) We accept H₀ we are not able to support strategist´s claim
