Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :

For a square , 
⇒ 
⇒ 
⇒ 
⇒ 
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
One possibility is:
S = 6
M = 4
U = 5
T = 1
H = 3
I = 0
N = 9
K = 2
Step-by-step explanation:
If we replace the letters that are being added with:
S = 6
M = 4
U = 5
we have:

where T=1, H=3, I=0, N=9, K=2
Answer:
X can either be 7, or -10. You can prove this by plugging in the numbers yourself :)
Step-by-step explanation:
Please mark as brainliest
642 ion wanna show the work good luck doe
Answer:
40/3
Step-by-step explanation: