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2 years ago

Hello, here's the question :D

Mathematics

1 answer:

antoniya [11.8K]2 years ago

4 0

Answer:

(examples) n = 2

n = 3

n = 4

Step-by-step explanation:

to demonstrate, all you do is select a number to represent 'n' and plug it in.

so for example, n = 2:

2(2) + 3(2) = 5(2)

4 + 6 = 10, which is true.

You might be interested in

There are 325 children at the zoo . If 64% of children are boys and the

aleksandr82 [10.1K]

Answer:

117 Girls

Step-by-step explanation:

If 64% of the kids are boys, then 36% are girls 64% + 36% = 100%

.36 x 325 = 117 girls

Proof

.64 x 325 = 208 boys

208 + 117 = 325

4 0

3 years ago

5(3a-1)-2(3a-2)=3(a+2)+v

STatiana [176]

Answer:

<u>The answer is option C. 6a-7</u>

Step-by-step explanation:

Given that

5(3a-1)-2(3a-2)=3(a+2)+v

Solve for v

∴ v = 5(3a-1)-2(3a-2) - 3(a+2)

∴ v = 15a - 5 - 6a + 4 - 3a - 6

∴ v = 15a - 6a - 3a - 5 + 4 - 6

∴ v = 6a - 7

<u>So the answer is option C. 6a-7</u>

5 0

3 years ago

What is 0.00001 meters in nanometers

Luden [163]

The answer is 10000 because you need to flip it

5 0

3 years ago

Read 2 more answers

Silvio wants to find the perimeter of quadrilateral ABCD. He begins by computing the length of side AB using the distance formul

saveliy_v [14]

Answer:

Step-by-step explanation:

AB = √(-4)² + (-3)²

AB = √ 16 + 9

AB = √ 25

AB = 5

AD = 4 ; DC = 4 ; BC = 7

Perimeter = 5 + 4 + 4 + 7 = 20 units

3 0

2 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$

$9 + {x}^{2} = 25$

${x}^{2} = 16$

$x = 4$

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

$- \frac{3}{5} \times \frac{5}{13} + - \frac {4}{5} \times \frac{12}{13}$

$- \frac{15}{65} + ( - \frac{48}{65} )$

$- \frac{63}{65}$

Hope this helps

6 0

2 years ago