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klio [65]
3 years ago
11

Given the linear equation y = 10x - 11.

Mathematics
1 answer:
grigory [225]3 years ago
4 0
Y 10x - 13 should be right
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Lillian works 7hours each day for 5 days a week she earn £420 each week how much does she earn per hour
frosja888 [35]

Answer:

£12 per hour

Step-by-step explanation:

7 × 5 = 35 hours

35 h : 420

1 h : x

x = 420×1 / 35

= £12 per hour

8 0
3 years ago
Can someone help me out with number 2?
Norma-Jean [14]
\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot  \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot  \frac{ \sqrt{2} }{2}=-      \frac{ \sqrt{6} }{4} -  \frac{ \sqrt{2} }{4}=  -\frac{  \sqrt{6}+\sqrt{2} }{4}

5 0
3 years ago
Anna had $54 in her purse. She bought a book for $26.34 and a book marker for $1.27. Anna’s mom then gave her $10 for completing
jekas [21]

Answer:

Anna has $36.39 dollars.

Step-by-step explanation:

All we have to do is subtract

54 - (26.34 + 1.27) =

54 - 27.61 =

36.39

So, the answer is 36.39

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ
Rudik [331]
This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5)   or approximately
=0.00006181
7 0
3 years ago
If 2 years on earth equals 5 months in another dimension, what are the equations to find the time in earth and that other dimens
Ede4ka [16]

Let x be the length of a month on the other dimension. Since a year value is 365.242 days

We have 2 × 365.242 = 5 × x

It means that 5x = 730,484

and that x = 730,484 / 5 ≈ 146,1 days rounded to the decimal

This means that a month length in the other dimension is of roughly 146 days.. and If we assume that a month in the other dimension is of 30 days approximately, then one day length would be of 146,1 / 30 ≈ 4.87 days

6 0
3 years ago
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