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Liula [17]
3 years ago
10

A dilation produces a smaller figure. Which is a possible scale factor?

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:

:the picture dosent load bro

Step-by-step explanation:

Bumek [7]3 years ago
6 0

I can't see pictures, but any number under 1 shrinks and image.

Edit: I saw your comment. It's B, because it is the only one below 1

---

sorry if this doesn't help

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Find the volume of a rectanglular prism if the length is x and the width is x^2 and the height is 5x^2 +4x+1. Use the formula v=
My name is Ann [436]

Answer:

The volume = 5x^{5}+4x^{4}+x^{3}

Step-by-step explanation:

* The rule of the volume of the rectangular prism:

- the volume of any prism = base area × height

∵ The base of the rectangular prism is rectangle

∵ Area any rectangle = Length × Width = l × w

∴ The volume of the rectangular prism = l × w × h

* In the problem:

∵ l = x , w = x² , h = 5x² + 4x + 1

∴ The volume = (x)(x²)(5x² + 4x + 1)

* We will simplify it

- Multiply x by x² and then multiply the answer by the bracket

∵ x × x² = x³

∴ x³(5x² + 4x + 1)

∵ x³ × 5x² = 5x^5

∵ x³ × 4x = 4x^4

∵ x³ × 1 = x³

∴ The volume = 5x^{5}+4x^{4}+x^{3}

5 0
3 years ago
A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
John bought candy for $4.50 per pound.He spent a total of $36.00.How many pounds of candy did he buy?
ExtremeBDS [4]

Answer:

8 pounds. 36/4.5 is 8 so that's the answer

3 0
3 years ago
What is the square root of 864
skelet666 [1.2K]

There are two ways to evaluate the square root of 864: using a calculator, and simplifying the root.

The first method is simplifying the root. While this doesn't give you an exact value, it reduces the number inside the root.

Find the prime factorization of 864:

\sqrt{864} = \sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3}

Take any number that is repeated twice in the square root, and move it outside of the root:

\sqrt{864} = \sqrt{(2 \cdot 2) \cdot (2 \cdot 2) \cdot 2 \cdot (3 \cdot 3) \cdot 3}

\sqrt{2 \cdot 2} = \sqrt{4} = 2

\sqrt{3 \cdot 3} = \sqrt{9} = 3

\sqrt{(2 \cdot 2) \cdot (2 \cdot 2) \cdot 2 \cdot (3 \cdot 3) \cdot 3} = \sqrt{(4) \cdot (4) \cdot 2 \cdot (9) \cdot 3}

\sqrt{(4) \cdot (4) \cdot 2 \cdot (9) \cdot 3} = (2 \cdot 2 \cdot 3) \sqrt{2 \cdot 3} = \boxed{12 \sqrt{6}}

The simplified form of √864 will be 12√6.

The second method is evaluating the root. Using a calculator, we can find the exact value of √864.

Plugged into a calculator and rounded to the nearest hundredths value, √864 is equal to 29.39. Because square roots can be negative or positive when evaluated, this means that √864 is equal to ±29.39.

6 0
3 years ago
PLS HELP GIVING 11 POINTS
Svetradugi [14.3K]

Answer:

3. 40 4. 132

Step-by-step explanation:

you multiply the length and the width

8 0
2 years ago
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