Solution:
To find the equation of line passing through points A (1, 3) and B (3, 7).
we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points 
and 
is given by - 
.
Slope of the line at point A(1,3) and B(3,7)
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Equation of a line using a point and a slope , 
The equation of line passing through points A (1, 3) and B (3, 7) :
Answer:
angles A and B
Step-by-step explanation:
the side of a triangle is denoted by naming with its vertices that are joined in forming the side. so here vertices A and B are included for side AB.
∴ The angles included are A and B
In two years tom will become 10 years old
Because 5×2=10
Answer:
m∠BAC = 105°
m∠FAB = 75°
Step-by-step explanation:
By using the property of an exterior angle of a triangle,
Measure of an exterior angle is equal to the sum of opposite two angles of a triangle.
From the triangle given in the picture,
m∠ABC + m∠BCA + m∠CAB = 180°
(13x - 3)° = (3x + 2)° + 55°
13x - 3 = 3x + 57
13x - 3x = 57 + 3
10x = 60
x = 6
m∠FAB = (13x - 3)° = 75°
m∠ABC = (3x + 2)° = 20°
Since, ∠BAC and ∠FAB are the linear pair of angles,
m∠BAC + m∠FAB = 180°
m∠BAC + 75° = 180°
m∠BAC = 180° - 75° = 105°
