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3 years ago

Please answer fast I have an exam tomorrow

Mathematics

2 answers:

Blababa [14]3 years ago

5 0

Answer:

A. no solution

Step-by-step explanation:

Hope this helped, Have a Great Day!!

RideAnS [48]3 years ago

5 0

Answer:

No solution maybe that's the answer. By the way, all the best

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from the top of an 800 foot tall car talk tower, tom sees a plane; the angle of elevation is 67 degrees. at the same instant tay

AlekseyPX

Answer:

Height of plane = 25971.7 meters

Step-by-step explanation:

let H =height of plane

Let x = distance ray to the point under the plane

800 foot = 245meters

1 mile = 1609meters.

Tan 81 = $\frac{H}{1609+x}$ -----------------------(1)

Tan 67 = $\frac{H-245}{x}$ -----------------------(2)

6.3134 = $\frac{H}{1609+x}$ ------------------------(3)

2.3556 = $\frac{H-245}{x}$ -----------------------(4)

from (3) and (4)

H = 10158.26 + 6.3134x ---------------(a)

H = 245 + 2.2336x ---------------(b)

equating both (a) and (b) we have:

9913.26 = 3.9576x

x = 2504.74

Subst. x = 2504.74 into (a)

H = 25971.7meters

8 0

3 years ago

The price of Stock A at 9 A.M. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon,

Leya [2.2K]

Answer: 3.5

Step-by-step explanation:

8 0

3 years ago

Solve for x

andrew11 [14]

Answer:

Step-by-step explanation:

For example,

5×7-10>20

5(-3)-10<15

4 0

2 years ago

On a trip, Duke encounters some road construction that slows him down. While he is able to go 60 mph on the highway and 40 mph t

natulia [17]

Answer:

Time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

Step-by-step explanation:

Speed by which Duke travels a distance on highway $d_1$ = 60 mph

Let the time taken to travel on highway = $t_1$ hours

Distance traveled = $60t_1$ miles

Speed in the city = 40 mph

Let the time taken = $t_2$ hours

Distance traveled in the city = $40t_2$ miles

Speed on the construction = 20 mph

Let the time spend on the construction = $t_3$ hours

Distance traveled on the construction = $20t_3$ miles

Since, total distance covered = 380 miles

$d_1+d_2+d_3=60t_1+40t_2+20t_3$

He spends one half the time on the highway as he does on the construction,

$t_3=2t_1$

Total time spent in the trip = 11 hours

Therefore, $t_1+t_2+t_3=11$

$t_1+t_2+2t_1=11$

$t_2=11-3t_1$

From equation (1),

$60t_1+40(11-3t_1)+20(2t_1)=380$

$60t_1-120t_1+40t_1+440=380$

$440-20t_1=380$

$20t_1=440-380$

$t_1=\frac{60}{20}$

$t_1=3$ hours

$t_2=11-3t_1=2$ hours

$t_3=2t_1=6$ hours

Therefore, time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

3 0

3 years ago

Members of the Wide Waters Club pay

vivado [14]

Answer:

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

Step-by-step explanation:

We can have two expressions to show the total cost paid by a member and non-member;

Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per summer season=$105

Cost per number of times they rent a boat=$9.50

Number of times they rent a boat=n

Replacing;

Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1

Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per number of times they rent a boat=$14.75

Number of times they rent a boat=n

Replacing;

Total cost by a non-member=(14.75×n)=14.75 n......equation 2

To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2

9.5 n+105=14.75 n

14.75 n-9.5 n=105

5.25 n=105

n=105/5.25

n=20

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

6 0

3 years ago