Answer:
Formula: (x, -y), when reflecting over the x-axis you keep the x-value the same, but change the sign of the y-value. For example: You have the original coordinates (3, 5), and if you reflect it over the x-axis it’ll be (3, -5).
Next time add an image, but know that the expression is equal to 657 since..
83 * 8 -7
Use PEMDAS
664 - 7
657
The answer is
<span>y = four thirdsx + 8
</span>
Answer:

Step-by-step explanation:
We need to rationalize the denominator of
. For rationalizing we multiply the equation by 
So, solving
