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3 years ago

WILL GIVE BRAINLIEST!!! What is your favorite color?

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

Magenta

Step-by-step explanation:

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Make p the subject of the formula q-2p=p+4

Nutka1998 [239]

Answer:

q-2p=p+4

q-4=p+3p

p=(q-4)/3is answer

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3 years ago

What is the slope of the line shown?

earnstyle [38]

Answer:

The slope is 45.

Step-by-step explanation:

Using the slope formula by two points:

m=(y2-y1)/(x2-x1)

m=(210-120)/(4-2)

m=45

7 0

2 years ago

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An equilateral triangle has perimeter P. The length of one side is P/3. Which expression is equivalent to the length on one side

irina1246 [14]

Answer: $3\times \dfrac{P}{3}=P$

Step-by-step explanation:

Given

The perimeter of one equilateral triangle is P

The lengths of the equilateral triangle are equal

Suppose x is the length of each side

$\therefore 3\times x=P\\\\\Rightarrow x=\dfrac{P}{3}$

i.e.

$\Rightarrow 3\times \dfrac{P}{3}=P$

3 0

3 years ago

WHAT IS THIS ANSWER ASAP!!!

weeeeeb [17]

Answer:

(～￣▽￣)～Hope this helps!

8 0

3 years ago

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

<em>a. The system of equations that models the situation is....</em>

<em>b. The solution to the system: x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0

4 years ago