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Arte-miy333 [17]
3 years ago
5

Is this a function ?

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

it is a function

Step-by-step explanation:

the input is not repeated

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Look at the three dimensional solid below
Sever21 [200]

Answer:

A.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write an equivalent expression for 25x - 45 using the properties of operations. Hint: find the GCF of 25 and 45. You use parenth
Oksana_A [137]

Answer:

25x - 45 = 5(5x - 9)

Step-by-step explanation:

Find the greatest common factor (GCF) of 25 and 45.

You can do this several ways, but one way is to list all the factors of both numbers and find the greatest common one:

Factors of 25: 1, 5, 25

Factors of 45: 1, 3, 5, 9, 15, 45

Therefore, 25 and 45 have 2 common factors: 1 and 5

So the greatest common factors is 5

25x - 45 = 5(ax - b)

To find the value of a, simply divide 25 by 5: 25 ÷ 5 = 5

To find the value of b, divide 45 by 5: 45 ÷ 5 = 9

25x - 45 = 5(5x - 9)

3 0
2 years ago
Please help i'm not that good at math. Determine the number of real solutions for each system of equations.
ratelena [41]

System A has ONE real solution

System B has NO real solutions

System C has ONE real solution

7 0
3 years ago
Read 2 more answers
Which expression has the same value as 4÷25 in fraction form
otez555 [7]

Answer:

4/25

Step-by-step explanation:

It is a fraction with 4 in the numerator and 25 in the denominator.

4

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25

6 0
3 years ago
Explain (1+y)^2 how does it turn into 1+2y+y^2 ? i don't understand
Greeley [361]
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)
6 0
3 years ago
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