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erma4kov [3.2K]
3 years ago
8

1. Elijah's puppy weighs 35 ounces. If he weighed 20 ounces at the last visit to the veterinarian's office, what is the percent

increase in the
puppy's weight?
The percent increase is type your answer...
Mathematics
1 answer:
disa [49]3 years ago
6 0

Answer:

75 percent

Step-by-step explanation:

percent increase = increase/original ×100

= (35-20)/20 ×100 =15/20 ×100= 15×5= 75

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Trapezoid LMNP was reflected using the rule
Bingel [31]

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c i think

Step-by-step explanation:

not sure

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Which of the following ordered pair could NOT be included in this set if it is a function?
AlexFokin [52]

Answer:

B is the right answer and if you add

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3 years ago
It costs $10.99 per month for an online video streaming service. Jackie watched 28 videos in one month. What was the price per v
Kitty [74]

Answer:

Assuming it's actually charging per video, and not just for a subscription, the cost per video would be .40 (40 cents per movie)

Step-by-step explanation:

10.99 / 28 =

.3925

Which rounded up is .40

3 0
4 years ago
An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra
ruslelena [56]

Answer:

E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6

E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2

V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|

<em>Point a:</em>

  • The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is

E(X) = $\sum_{x\in D} x\cdot p(x)

Therefore

E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6

  • If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by

E[h(X)] = $\sum_{D} h(x)\cdot p(x)

So h(X) = X^2 and

E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2

  • The variance of X, denoted by V(X), is

V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2

Therefore

V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24

<em>Point b:</em>

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

E(aX+b)=a\cdot E(x)+b

We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore

The expected price paid by the next customer is

60\cdot E(X)-650=60\cdot 18.6-650=466

4 0
3 years ago
Help with mathhh tt​
Zepler [3.9K]

Answer:

wsp son

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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