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3 years ago

4. Which symbols are represented by an open circle on the number line? (Select all that apply.)

Mathematics

2 answers:

cupoosta [38]3 years ago

6 0

Answer:The first and second choice since those symbols are the ones that apply to open circle on the number line and the 2 last ones are closed circles

Step-by-step explanation:

Neko [114]3 years ago

3 0

Answer:

The first and second choice since those symbols are the ones that apply to open circle on the number line and the 2 last ones are closed circles

Step-by-step explanation:

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What are all the exact solutions of square root 2 cosx-1=0 for 0 less than or equal to x less than or equal to 2 pi ?Give your a

Lera25 [3.4K]

Answer: $x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}$

Step-by-step explanation:

Given equation is

$\sqrt{2}\cos x-1=0$

solving this

$\sqrt{2}\cos x=1\\\cos x=\frac{1}{\sqrt{2}}$

There can be two solution because $0$

$\cos x=\cos \frac{\pi }{4}\ or\ \cos (2\pi -\frac{\pi}{4})\\$

so, $x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}$

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3 years ago

You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the di

jek_recluse [69]

50x-y=x can be used to find it

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4 years ago

WILL GIVE BRAINLIEST!!

Elan Coil [88]

Answer:

x = 8

Step-by-step explanation:

6 0

4 years ago

Select the correct answer.

Vladimir [108]

Answer:

Step-by-step explanation:

The sum to n terms of a geometric series is

$S_{n}$ = $\frac{a(1-r^{n}) }{1-r}$

where a is the first term and r the common ratio

Here a = 6144 and r = $\frac{a_{2} }{a_{1} }$ = $\frac{3072}{6144}$ = $\frac{1}{2}$ , then

$S_{10}$ = $\frac{6144(1-(\frac{1}{2}) ^{10}) }{1-\frac{1}{2} }$

= $\frac{6144(1-\frac{1}{1024}) }{\frac{1}{2} }$

= 12288(1 - $\frac{1}{1024}$ ) ← distribute

= 12288 - 12

= 12276 → B

4 0

3 years ago

A firecracker shoots up from a hill 145 feet high with an initial speed of 80 feet per second. Using the formula H(t) = -16t2 +

kiruha [24]

145 = -16 t² + 80 t +s
s = ?
v = v0 - at
0 = 80 - at
80 = at
s = 80 t - at²/2
s = 80 t - 80t/2
s = 40 t
Finally: 145 = -16 t² + 80 t + 40 t
16 t² - 120 t + 145 = 0
We will solve this quadratic equation:
t = [120 +√ ( (-120)²- 4 · 16 · 145 )] / 32
t = [120 + √ (14400 - 9280) ] / 32
t = (120 + 71.55) / 32 = 5.98 ≈ 6 s
Answer:D) 6 seconds

3 0

3 years ago