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ozzi
3 years ago
12

4. Which symbols are represented by an open circle on the number line? (Select all that apply.)

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0

Answer:The first and second choice since those symbols are the ones that apply to open circle on the number line and the 2 last ones are closed circles

Step-by-step explanation:

Neko [114]3 years ago
3 0

Answer:

The first and second choice since those symbols are the ones that apply to open circle on the number line and the 2 last ones are closed circles

Step-by-step explanation:

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What are all the exact solutions of square root 2 cosx-1=0 for 0 less than or equal to x less than or equal to 2 pi ?Give your a
Lera25 [3.4K]

Answer: x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}

Step-by-step explanation:

Given equation is

\sqrt{2}\cos x-1=0

solving this

\sqrt{2}\cos x=1\\\cos x=\frac{1}{\sqrt{2}}

There can be two solution because 0

\cos x=\cos \frac{\pi }{4}\ or\ \cos (2\pi -\frac{\pi}{4})\\

so, x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}

3 0
3 years ago
You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the di
jek_recluse [69]
50x-y=x can be used to find it
4 0
4 years ago
WILL GIVE BRAINLIEST!!​
Elan Coil [88]

Answer:

x = 8

Step-by-step explanation:

6 0
4 years ago
Select the correct answer.
Vladimir [108]

Answer:

B

Step-by-step explanation:

The sum to n terms of a geometric series is

S_{n} = \frac{a(1-r^{n}) }{1-r}

where a is the first term and r the common ratio

Here a = 6144 and r = \frac{a_{2} }{a_{1} } = \frac{3072}{6144} = \frac{1}{2} , then

S_{10} = \frac{6144(1-(\frac{1}{2}) ^{10}) }{1-\frac{1}{2} }

     = \frac{6144(1-\frac{1}{1024}) }{\frac{1}{2} }

     = 12288(1 - \frac{1}{1024} ) ← distribute

     = 12288 - 12

     = 12276 → B

4 0
3 years ago
A firecracker shoots up from a hill 145 feet high with an initial speed of 80 feet per second. Using the formula H(t) = -16t2 +
kiruha [24]
145 = -16 t² + 80 t +s
s = ?
v = v0 - at
0 = 80 - at
80 = at
s = 80 t - at²/2
s = 80 t - 80t/2
s = 40 t
Finally: 145 = -16 t² + 80 t + 40 t
16 t² - 120 t + 145 = 0
We will solve this quadratic equation:
t = [120 +√ ( (-120)²- 4 · 16 · 145 )] / 32
t = [120 + √ (14400 - 9280) ] / 32 
t = (120 + 71.55) / 32 = 5.98 ≈ 6 s
Answer:D) 6 seconds
3 0
3 years ago
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