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saveliy_v [14]
2 years ago
5

6. Z1 and 22 are vertical angles. If the measure of Z2 is 105°, find the measure of

Mathematics
1 answer:
Rashid [163]2 years ago
3 0

Answer:

Z1 is also 105°

Step-by-step explanation:

this is because vertical angles are always equal

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Square WXYZ dilates by a factor of 1/3 with respect to the origin to create W'X'Y'Z'. If W'X' is 6 units, what is WX? *
zvonat [6]

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well you should firstcalculate the distance then divide by the primary source and you should be able to get the answer after substituting

Step-by-step explanation:

6 0
2 years ago
3. How many solutions does the system of equations have?
miskamm [114]

Answer:

oof i dont know this

Step-by-step explanation:


5 0
2 years ago
The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased
taurus [48]

Answer:

2010.

Step-by-step explanation:

We have been given an exponential growth formula P(t)=466\cdot 1.035^t, which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

900=466\cdot 1.035^t

\frac{900}{466}=\frac{466\cdot 1.035^t}{466}1.9313304721030043=1.035^t

Take natural log of both sides:

\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)

0.658209129198=t\cdot 0.034401426717

\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}

19.1331927775=t\\\\t=19.1331927775

This means that in the 20th year since 1990, 900 million passengers would travel by airline.

1990+20=2010

Therefore, 900 million passengers would travel by airline in 2010.

6 0
2 years ago
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
Max wants to cover this rectangle with blue tiles I estimate that there would be
Sladkaya [172]

I have no idea. Where is the diagram.

8 0
2 years ago
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