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3 years ago

Can someone help me please I need to turn this in fast :(

Mathematics

1 answer:

Len [333]3 years ago

8 0

I believe it is answer A...He pays 485 originally and then 25 to his brother ever hour so 485+75 is 560 making A the answer.

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Given that the base of the rock is 14 feet, and the height of the rock is 12 feet, what is the slope on which the vehicle is lea

ExtremeBDS [4]

Hi! So pretty much to find slope of a triangle you are going to use rise/run. The height being 12 and the length is 14. You get 12/14. Simplified is going to be 6/7. :)

4 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

Which interval has the most students? 0-4 5-9 10-14 15-19

-Dominant- [34]

The answer is 0-4 it has more

8 0

3 years ago

Read 2 more answers

Como se calcula la medida de la sircunferencia si conocen la medida del diámetro

anygoal [31]

Para encontrar la medida de la circunferencia se aplica la ecuación P = π*D.

Explicación.

El perímetro es la medida total de todos los lados que pueda tener una figura geométrica, además se tiene que tener en cuenta que es una magnitud fundamental de los polígonos.

Para una circunferencia el perímetro se encuentra multiplicando el diámetro y el número π (pi), como se muestra a continuación:

P = π*D

Dónde:

P es el perímetro.

D es el diámetro

4 0

3 years ago

Make a table of values, then graph. y = 2x + 1

hram777 [196]

I put the answer below in the picture!

7 0

3 years ago