Let the function f be continuous and differentiable for all x. Suppose you are given that f(−1)=−3, and that f'(x) for all value
s of x. Use the Mean Value Theorem to determine the largest possible value of f(5).
1 answer:
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Answer:
1.548 gallons
Step-by-step explanation:
Length of the rectangular wall = 25.1 ft.
Width of the rectangular wall = 18.5 ft.
Area of the rectangular wall = length * width = 25.1 * 18.5
= 464.35 square feet
300 square feet wall can be painted using 1 gallon of paint.
=> 1 square feet wall can be painted using gallon of paint.
=> 464.35 square feet wall can be painted using gallon of paint.
= 1.548 gallons of paint
Answer:
A) x = 20
Step-by-step explanation:
ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.
Since, diagonals of a rhombus are perpendicular bisector.
assuming
Then the column values for base five here are
5³ 5²
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus =
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219