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butalik [34]
3 years ago
6

Somebody Come In Clutch!!!!

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

I think its B. (OwO)

Step-by-step explanation:

In Mathematics, the circle with horizontal line through stands for a Greek letter called ''Theta''. ... Theta (θ ) is a symbol used to denote the unknown measure of an angle. It is used mostly in displaying the trigonometric ratios of sine, cosine, and tangent.

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What is the solution? 21=42−3r r=−8 r=−7 r = 7 r = 8
faltersainse [42]
R=-7, you have to put each answer in the equation, therefore; 21=42-3(-7) So you have to do multiplication (PEMDAS, if you arent aware of that acronym then it stands for the order of what to do with an equation, Parentheses get solved first, then Exponents, then multiplication, then division, then addition, then finally subtraction. Solving in that order will solve your answer correctly.) With -3 times -7 which gives you 21. Then you do 42 - 21 which equals 21. So 21 = 21.
7 0
3 years ago
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Operations with rational expressions
Scorpion4ik [409]

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

Solution:

Given expression:

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}

To solve the given expression:

First simplify: \frac{50-2 w^{2}}{3 w^{2}+9 w-30}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}

Cancel the common factor (w + 5).

                      $=-\frac{2(w-5)}{3(w-2)}

Now substitute this in the given expression.

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}

Multiply the fractions \frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}

Factor the denominator 3(w-2)(6 w-30) =18(w-2)(w-5)

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}                        

Cancel the common factor 2(w – 5).

                               $=-\frac{w^{2}+5 w-14}{9(w-2)}

Factor the numerator w^{2}+5 w-14=(w-2)(w+7)

                               $=-\frac{(w-2)(w+7)}{9(w-2)}

Cancel the common factor (w – 2).

                               $=-\frac{w+7}{9}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

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Which represents a function?
Sedaia [141]

Answer:

C

Step-by-step explanation:

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What is larger 8/10 or 63/100
amid [387]

Answer:

8/10

Step-by-step explanation:

8/10 = 80/100 > 63/100

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How do I simplify this?
storchak [24]
Rise over run or the change in Y over the change in X
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