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erik [133]
3 years ago
15

How do I simplify this?

Mathematics
1 answer:
storchak [24]3 years ago
3 0
Rise over run or the change in Y over the change in X
You might be interested in
What is 4(3+x) and how do I solve it
anastassius [24]

Answer:

12 + 4x

Step-by-step explanation:

To solve this you would have to use the distributive property.

The problem would basically go like this.

4 (3+x)

(Distribute)

(4x3) (4 x X)

4x3 = 12, 4 x x = 4x

So the answer would be 12 +4x

Hope this helps :)

3 0
3 years ago
Read 2 more answers
Find the area of the irregular polygon, pls hurry I need this quickkkkkk
pickupchik [31]

Answer:

To find the area of an irregular polygon you must first separate the shape into regular polygons, or plane shapes. You then use the regular polygon area formulas to find the area of each of those polygons. The last step is to add all those areas together to get the total area of the irregular polygon

and i thank that it is b 120  in2

8 0
3 years ago
What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?
9966 [12]

Answer:

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07  (One tailed test )

Step-by-step explanation:

For n=6  the degrees of freedom will be n-1 = 5 .

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07  (One tailed test )

The critical region depends on ∝ and the alternative hypothesis

a) When Ha is σ²≠σ² the critical region is

χ²  < χ²(1-∝/2)(n-1) and  χ² > χ²(1-∝/2)(n-1)   Two tailed test

( χ²  < 0.83) and ( χ²  > 0.83)

b) When Ha is σ²> σ² the critical region falls in the right tail and its value is

 χ² > χ²(∝)(n-1)   One tailed test  {11.07  (One tailed test )}

c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value  

χ²(1-∝)(n-1)  One tailed test  (1.145)

6 0
3 years ago
Read 2 more answers
Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911
nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

\lambda=\dfrac{1}{2}

(a) What is the expected number of 911 calls in one hour?

\lambda=\dfrac{1}{2}\times 60=30

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

\lambda=\dfrac{1}{2}\times 5=2.5

Number of calls = 3

So, P(X=3) is given by

P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820

Hence, a) 30, b) 0.2138, c) 0.0820

4 0
3 years ago
1) What equation is used in the function table below?
Neporo4naja [7]

Answer:

y = -3x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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