Find an equivalent fractions for each given fraction 4/10

Anit [1.1K]

Answer:

1. 62.95

2. 63.37

3. 63.7

Step-by-step explanation:

List the numbers by lining up the decimals and filling in zeros in the empty spaces to make all the numbers have the same number of digits, then compare whole numbers first then the decimals. There are two 63's so then you look at the decimal side one is .37 and one is .70 (add the zero so all numbers have the same number of digits)

63.37

62.95

63.70 (added the zero)

3 0

2 years ago

Given the following functions f(x) and g(x), solve f[g(6)]. f(x) = 6x + 12 g(x) = x − 8

iogann1982 [59]

Answer:

Answer:

Option 2nd is correct.

=0.

Step-by-step explanation:

Given the function:

Solve:

First calculate:

f[g(x)]

Substitute the function g(x)

Replace x with x-8 in the function f(x) we get;

The distributive property says that:

Using distributive property:

⇒

Put x = 6 we get;

Therefore, the value of is 0.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

3 years ago

NEEED HELPPPP ASAP PLEASEEE!!!! ONLY THE LAST ONE TO COMPLETE IM HAVING TROUBLE PLEASE

sergeinik [125]

The answer would be 1.52727...

To solve this, subtract 283-199 is 84. Then divide 84 by 55 since 55 is mph of the car. Then you would divide the 84/55. After, the calculation should be 1.52727...

So, the answer/ how much time it takes from Tallahassee to Live Oak is 1.5 hours. (1.52727, 1.53)

7 0

3 years ago

A business sells kicking tees by mail for 3 each the shipping charge is 5 the function p=n+5 shows how the number of tees n rela

melamori03 [73]

<u>Answer: </u>

When you buy 2 , 3 and 4 tees , price you pay are 10.33 unit price , 13 unit price and 15.667 unit price respectively.

<u>Solution: </u>

Information provided in the question seems to be less . so assuming following two things.

1)Given function p = n + 5 do not include shipping cost as shipping cost is also dependent on number of tees.

2)If shipping charges for 3 tees is 5 , then shipping charges of 1 tee is $\frac{5}{3}$

When you buy 2 tees , n = 2

Price = p = n+5 = 2+5 = 7

Shipping charges =( $\frac{5}{3}$ ) x 2 = $\frac{10}{3}$

So total price you pay for two tees = 7 + ( $\frac{10}{3}$ ) = 7 + 3.3333 = 10.3333 unit price.

When you buy three tees , n = 3

Price = p = n+5 = 3+5 = 8

Shipping charges =( $\frac{5}{3}$ ) x 3 = 5

So total price you pay for two tees = 8 + 5 = 13 unit price.

When you buy four tees, n = 4

Price = p = n+5 = 4+5 = 9

Shipping charges =( $\frac{5}{3}$ ) x 4 = $\frac{20}{3}$

So total price you pay for two tees = 9 + ( $\frac{20}{3}$ ) = 47/3 = 15.667 unit price.

Hence when you buy 2 , 3 and 4 tees , price you pay are 10.33 unit price , 13 unit price and 15.667 unit price respectively.

3 0

3 years ago