Strong, they are all close together and close to the line.
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The equation of the function is y = 4x + 5. Find the value of y when
x = 3
x = -2
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
y = 4x + 5 [Equation]
<h3>To Find:-</h3>
The value of y when x = 3 , x = -2
<h2>Solution:-</h2>
y = 4x + 5 [Given equation]
When x = 3 ,
y = 4 × 3 + 5 [Value of x is 3]
y = 12 + 5
<h3>y = 17 [Answer]</h3>
Again, when x = -2 ,
y = 4 × (-2) + 5 [Value of x is -2]
y = -8 + 5
<h3>y = -3 [Answer]</h3>
Here is the equation:

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You need to get "x" by itself so minus 3 from each side

⇒

⇒

Divide 8 by 2

÷

x=4
So each 4 is equivalent to 4
Lets check:

⇒

⇒

So that means that Marcus practiced the piano for 4 hours and Donnel practiced for 7
If
, then
. You replace all x's in the function with -3.
![\begin{aligned}f(-3) &= |2(-3)+1|+5\\[0.5em]&= |-6+1|+5\\[0.5em]&= |-5|+5\endaligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Df%28-3%29%20%26%3D%20%7C2%28-3%29%2B1%7C%2B5%5C%5C%5B0.5em%5D%26%3D%20%7C-6%2B1%7C%2B5%5C%5C%5B0.5em%5D%26%3D%20%7C-5%7C%2B5%5Cendaligned%7D)
Finish by evaluating the absolute value and then adding that to the 5 that's behind the absolute value.
Can you finish it from there?