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Firlakuza [10]
3 years ago
5

What's the polynomial standard form and degree of 8+3y^3 +8y+9y

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
Sorry if this is annoying but I need to ask questions on this app so I’m answering random questions LOL
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What is 3/4 of 4/5= ​
r-ruslan [8.4K]

Answer:

answer: 15/16 Hope this helps!

4 0
2 years ago
Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is
Sholpan [36]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars). The listed values correspond to cars​ A, B,​ C, D,​ E, F, and​ G, respectively.

514 541 302 400 507 406 369

Find the

a.​ mean,

b.​ median,

c.​ midrange,

d. mode for the data.

Also complete parts e. and f.

e. Which car appears to be the safest?

f. Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

Answer:

a) Mean = 434.14

b) Median = 406

c) Midrange = 421.5

d) Mode = 0

e) Car C appears to be the safest

f) The small cars does not appear to have about the same risk of head injury in a crash.

Step-by-step explanation:

We are given the head injury measurements from small cars that were tested in crashes.

The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion.

The listed values are;

A = 514

B = 541

​C = 302

D = 400

​E = 507

F = 406

G = 369

a)​ Mean

The mean of the measurements is given by

Mean = Sum of measurements/ Number of measurements

Mean = (514 + 541 + 302 + 400 + 507 + 406 + 369)/7

Mean = 3039/7

Mean = 434.14

b)​ Median

Arrange the measurements in ascending order (low to high)

302, 369, 400, 406, 507, 514, 541

The median is given by

Median = (n + 1)/2

Median = (7 + 1)/2

Median = 8/2

Median = 4th

Therefore, the 4th measurement is the median that is 406

Median = 406

c)​ Mid-range

The midrange is given by

Midrange = (Max + Min)/2

The maximum measurement in the data set is 541

The minimum measurement in the data set is 302

Midrange = (541 + 302)/2

Midrange = 843/2

Midrange = 421.5

d)​ Mode for the data

The mode of the data set is the most repeated measurement.

302, 369, 400, 406, 507, 514, 541

In the given data set we don't have any repeated measurement therefore, there is no mode or we can say the mode of this data set is 0.

Mode = 0

e) Which car appears to be the safest?

Since we are given that the measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars)

The lowest hic value corresponds to car C that is 302

Therefore, car C appears to be the safest among other cars.

f) Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

302, 369, 400, 406, 507, 514, 541

As you can notice, the hic values differ a lot from each other therefore, we can conclude that the small cars does not appear to have about the same risk of head injury in a crash.

8 0
3 years ago
I'd appreciate the help, its making my brain hurt plus i never was good at algebra
Andrei [34K]

Answer: I got -2

I plugged -6 in for y and then simplified. -6 x -6 = 36. 7 x -6 = -42. So 36 - 42 = -6. -6 + 4 = -2

3 0
2 years ago
A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex
kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

325 mg + 2mg+15 mg=342 mg

The percentages of each component in the formula are:

Acetaminophen:\frac{325mg*100}{342mg}=95.03%

Chlorpheniramine maleate:\frac{2mg*100}{342mg} =0.58%

Dextromethorphan hydrobromide:\frac{15mg*100}{342mg}=4.39%

If 1 Kg=10^{6} mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

\frac{10^{6} mg *0.58}{95.03}=6153.85 mg

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

\frac{10^{6}mg*100}{95.03}=1052307.7mg

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

\frac{1052307.7mg}{342mg}=3076.923

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.

7 0
3 years ago
Need help on 60 please!
barxatty [35]
Thousand=2,000
ten thousand=7,000
hundred thousand=100,072,055(i think :/ )
million(not sure) 10million?
3 0
3 years ago
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