Let f(x)=0, you'll get x=3 and x=-5, those are the x-intercepts of the function.
<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>
Note that the domain of h is <span>[0,∞]</span>.
By differentiating,
<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>
by factoring out <span>34</span>,
<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>
by finding the common denominator,
<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>
<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>
Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.
Hence, the critical numbers are <span>t=0,1</span>.
I hope that this was helpful.
Let the acute angle be 2x.
Its complement is 90 - 2x.
It is given that this complementary angle is less than each of the bisected angle.
Therefore, 90 - 2x < x
90 < 3x
or, x > 30.
2x > 60
Therefore, the statement is true for all angles that are greater than 60 degrees.
Answer: The answer is 1, 2
Step-by-step explanation:
