Evaluate n + 11 for n = 3. ! plz help 8 14 33 311

If 4sintheta = -3, solve for theta given 0°>_theta>_360°

Soloha48 [4]

Answer:

311.41 degrees

Step-by-step explanation:

If 4 sin Ф = -3 and Ф is between 0 and 360 degrees, then we conclude that Ф must be either in Quadrant III or Quadrant IV (because the sine is negative).

Let's assume we're in Quadrant IV. Then sin Ф = opp / hyp = -3/4; that is, the opp side is negative and has length 3, and the hypo is positive 4.

According to the Pythagorean Theorem, (-3)^2 + x^2 = 4^2, or,

x^2 = 16 - 9 = 7.

Then x is either √7 or -√7.

To find the angle Ф, use the inverse sine function:

Ф = arcsin (-3/4). Using a calculator we get the angle -40.59 degrees, which corresponds to (360 degrees - 40.59 degrees), or 311.41 degrees. We can check this by finding the sine of 311.41 degrees; the result is -0.75, which matches "If 4sintheta = -3."

6 0

3 years ago

Which of these inequalities has no solutions?

Mila [183]

Answer:

b. √x<-14

Step-by-step explanation:

square roots are never negative

8 0

3 years ago

How to solve 4/7y-2 = 3/7 + 3/14

lisabon 2012 [21]

Solution

1) Simplify $\frac{4}{7y}$ to $\frac{4y}{7}$
$\frac{4y}{7}$ −2= $\frac{3}{7}$ + $\frac{3}{14}$

2) Simplify $\frac{3}{7}$ + $\frac{3}{14}$ to 914
 $\frac{4y}{7}$ −2= $\frac{9}{14}$

3) Add 2 to both sides
 $\frac{4y}{7}$ = $\frac{9}{14}$ +2

4) Simplify $\frac{9}{14
}$ +2 to $\frac{37}{14}$
$\frac{4y}{7}$ = $\frac{37}{14}$

5) Multiply both sides by 7
4y= $\frac{37}{14}$ ×7

6) Simplify $\frac{37}{14}$ ×7 to $\frac{259}{14}$
$\frac{4y}{7}$ = $\frac{259}{14}$

7) Simplify $\frac{259}{14}$ to $\frac{37}{2}$
$\frac{4y}{7}$ = $\frac{37}{2}$

8) Divide both sides by 4
y= $\frac{37}{2}$ ×4

9) Simplify 2×4 to 8
y= $\frac{37}{8}$

Hope this helps

5 0

3 years ago

On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)

aleksandr82 [10.1K]

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = $(\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})$