With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.
Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
,
,
,
,
,
,
,
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
Sus amoogussus amoogsus susy abaka
1)
y = kx
-12 = k(9)
k = -4/3
y = (-4/3)(-4)
y = 16/3
2)
y = kx
8 = 20k
k = 2/5
y = (2/5)(10)
y = 4
3)
y= kx
-6 = k(-14)
k = 3/7
-4 = (3/7)x
-4(7/3) = x
x = -28/3