Answer:
Area V
Step-by-step explanation:
3/4 divided by 1/5 = 3 3/4
Hope that helps :)
Answer:
vertex = ( -6 , -3 )
focus = 
axis of symmetry = y = -3
directrix = x = 
GRAPH :
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real