You multiply each side of the equation by 16 .
=
Cross multiply
12x=900 Divide both sides by 12.
x=75 hammers to begin with.
Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
Answer: she wants to rent the car for 11 days.
Step-by-step explanation:
Let x represent the number of additional days that Pamela wants to rent the car for.
Customers can pay $40 to rent a compact car for the first day plus $6 for each additional day. This means that the total cost of using this special for x days would be
40 + 6(x - 1) = 40 + 6x - 6
= 34 + 6x
Also, they can rent the same car for $30 the first day and $7 for every additional day beyond that. This means that the total cost of using this special for x days would be
30 + 7(x - 1) = 30 + 7x - 7
= 23 + 7x
Since she found out that the two specials are equivalent for x days, then
34 + 6x = 23 + 7x
7x - 6x = 34 - 23
x = 11
