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sergeinik [125]
3 years ago
5

Two angels are supplementary. The measure of the large angle is four more than three times the measure of the small angle. Find

the measure of both angles.
Mathematics
1 answer:
sashaice [31]3 years ago
5 0

Answer:

The measure of the two supplementary angles is

Small angle = x = 44°

Large angle = y = 136

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180° .

Let

Small angle = x

Large angle = y

x + y = 180°.... Equation 1

The measure of the large angle is four more than three times the measure of the small angle

Hence: y = 4 + 3x

We substitute 4 + 3x for y in Equation 1

x + 4 + 3x = 180°

4x + 4 = 180°

4x = 180° - 4

4x = 176

x = 176/4

x = 44°

Solve for y

y = 4 + 3x

y = 4 + 3(44)

y = 4 + 132

y = 136°

Therefore, the measure of the two supplementary angles is

Small angle = x = 44°

Large angle = y = 136

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30 adult tickets and 50 child tickets

Step-by-step explanation:

605 = 8.5a + 7c

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Hillary pours 10 cups of orange juice into glasses that hold 1 2/3 cup each. How many glasses does Hillary fill?
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10 =  \frac{30}{3 }  \\ 1 +  \frac{2}{3}  =  \frac{5}{3}  \\ \frac{30}{3}  \div  \frac{5}{3}  =  \frac{30}{3}  \times  \frac{3}{5}  = 8glasses

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3 years ago
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It's A, increased by a factor of 6.
8 0
3 years ago
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Angles A and B are located in the first quadrant such that sinA= 7/25 and cosB = 5/13. Determine the exact value for cos (A-B).
fomenos

Answer:

  204/325

Step-by-step explanation:

You can work this a couple of ways. We expect you are probably expected to use trig identities.

  cos(A) = √(1 -sin²(A)) = 24/25

  sin(B) = √(1 -cos²(B)) = 12/13

cos(A -B) = cos(A)cos(B) +sin(A)sin(B) = (24/25)(5/13) +(7/25)(12/13)

  = (24·5 +7·12)/325

cos(A -B) = 204/325

__

The other way to work this is using inverse trig functions. It is necessary to carry the full calculator precision if you want an exact answer.

  cos(A -B) = cos(arcsin(7/25) -arccos(5/13)) = cos(16.2602° -67.3801°)

  = cos(-51.1199°) ≈ 0.62769230 . . . . (last 6 digits repeating)

The denominators of 25 and 13 suggest that the desired fraction will have a denominator of 25·13 = 325, so we can multiply this value by 325 to see what we get.

  325·cos(A-B) = 204

so, the exact value is ...

  cos(A -B) = 204/325

8 0
3 years ago
What is the quadratic function f(x)=x^2+6x-2 In vertex form?
Yuliya22 [10]

Answer: Option D

f(x)=(x+3)^2 -k

Step-by-step explanation:

For a quadratic function of the form

ax ^ 2 + bx + c

The x coordinate of the vertice is:

x =-\frac{b}{2a}

In this case the function is:

f(x)=x^2+6x-2\\\\

So

a=1\\b=6\\c=-2

The x coordinate of the vertice is:

x=-\frac{6}{2*1}\\\\x=-3

The y coordinate of the vertice is:

f(-3) = (-3)^2 +6(-3) -2\\\\f(-3)=-11

The vertice is: (-3, -11)

The form e vertice for a quadratic equation is:

f(x)=(x-h)^2 +k

Where

the x coordinate of the vertice is h and the y coordinate of the vertice is k.

Then h=-3 and k =-11

Finally the equation f(x)=x^2+6x-2\\\\ in vertex form is:

f(x)=(x+3)^2 -k

6 0
3 years ago
Read 2 more answers
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