Answer:
Here we have the domain:
D = 0 < x < 1
And we want to find the range in that domain for:
1) y = f(x) = x
First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)
f(0) = 0 is the minimum in the range.
f(1) = 1 is the maximum in the range.
The range is:
0 < y < 1.
2) y = f(x) = 1/x.
In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.
f(0) = 1/0 ---> ∞
f(1) = 1/1
Then the range is:
1 < x.
Notice that we do not have an upper bound.
3) y = f(x) = x^2
This function is strictly increasing, then:
f(0) = 0^2 = 0
f(1) = 1^2 = 1
the range is:
0 < y < 1
4) y = f(x) = x^3
This function is strictly increasing in the interval, then:
f(0) = 0^3 = 0
f(1) = 1^3 = 1
the range is:
0 < y < 1.
5) y = f(x) = √x
This function is well defined in the positive reals, and is strictly increasing in our domain, then:
f(0) = √0 = 0
f(1) = √1 =1
The range is:
0 < y < 1
Answer: B, D, and E
0.85L
or
L-0.15L
or
L(1-0.15)
or


Step-by-step explanation:
L is the number of hours Landen spent at the beach. Mateo spent 15% less time. This means he spent 85% of it. So 0.85 times L. We can also calculate it by subtracting the difference between the two kids. - 15%. 15% is 0.15L or
. We subtract by L-0.15L or as
. This fraction can simplify to 
Answer:
Step-by-step explanation:
2/5 + x = 1
Multiply each term by 5
2 + 5x = 5
5x = 5 - 2
5x = 3
x = 3/5
Answer:
I wouldnt know.
Step-by-step explanation:
i think you forgot to attach the image, I’ll come back when you do. Just make sure to do that next time
Answer:
units
Step-by-step explanation:
The Line 1 has equation x + y = 5 ....... (1) , and
Line 2 has equation x + y = 3 .......... (2)
Now, we have to find the perpendicular distance between line 1 and line 2.
We can say that (3,0) is a point on line 2 as it satisfies the equation (2).
Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula
units (Answer)
We know that the perpendicular distance from any external point (
) to a given straight line ax + by + c = 0 is given by the formula
.