Let (-2, -3) represent A and (1, 1) represent B.
![d_A_B} =\sqrt{(X_A - X_B)^2 + (Y_A - Y_B)^2}](https://tex.z-dn.net/?f=%20d_A_B%7D%20%3D%5Csqrt%7B%28X_A%20-%20X_B%29%5E2%20%2B%20%28Y_A%20-%20Y_B%29%5E2%7D%20%20%20)
![d_A_B} =\sqrt{(-2 - 1)^2 + (-3 - 1)^2}](https://tex.z-dn.net/?f=%20d_A_B%7D%20%3D%5Csqrt%7B%28-2%20-%201%29%5E2%20%2B%20%28-3%20-%201%29%5E2%7D%20%20%20)
![d_A_B} =\sqrt{(-3)^2 + (-4)^2}](https://tex.z-dn.net/?f=%20d_A_B%7D%20%3D%5Csqrt%7B%28-3%29%5E2%20%2B%20%28-4%29%5E2%7D%20%20%20)
![d_A_B} =\sqrt{(9 +16}](https://tex.z-dn.net/?f=%20d_A_B%7D%20%3D%5Csqrt%7B%289%20%2B16%7D%20%20%20)
![d_A_B} =\sqrt{(25}](https://tex.z-dn.net/?f=%20d_A_B%7D%20%3D%5Csqrt%7B%2825%7D%20%20%20)
= 5
Answer: 5 units
Answer:
Option B. ![tan(60\°)=\sqrt{3}](https://tex.z-dn.net/?f=tan%2860%5C%C2%B0%29%3D%5Csqrt%7B3%7D)
Step-by-step explanation:
Let
y -----> the opposite side to angle of 60 degrees (or adjacent side to angle of 30 degrees)
x ----> the adjacent side to angle of 60 degrees (or opposite side to angle of 30 degrees)
we know that
The tangent of angle of 60 degrees is equal to divide the opposite side to angle of 60 degrees by the adjacent side to angle of 60 degrees
so
![tan(60\°)=\frac{y}{x}](https://tex.z-dn.net/?f=tan%2860%5C%C2%B0%29%3D%5Cfrac%7By%7D%7Bx%7D)
<em>Find the value of y</em>
Remember that
----> adjacent side to angle of 30 degrees by the hypotenuse
![cos(30\°)=\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=cos%2830%5C%C2%B0%29%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
so
![\frac{y}{4}=\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B4%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
![y=2\sqrt{3}\ units](https://tex.z-dn.net/?f=y%3D2%5Csqrt%7B3%7D%5C%20units)
<em>Find the value of x</em>
Remember that
----> opposite side to angle of 30 degrees by the hypotenuse
![sin(30\°)=\frac{1}{2}](https://tex.z-dn.net/?f=sin%2830%5C%C2%B0%29%3D%5Cfrac%7B1%7D%7B2%7D)
so
![\frac{x}{4}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B2%7D)
![x=2\ units](https://tex.z-dn.net/?f=x%3D2%5C%20units)
<em>Find the value of tan(60°)</em>
![tan(60\°)=\frac{y}{x}](https://tex.z-dn.net/?f=tan%2860%5C%C2%B0%29%3D%5Cfrac%7By%7D%7Bx%7D)
substitute the values of x and y
![tan(60\°)=\frac{2\sqrt{3}}{2}](https://tex.z-dn.net/?f=tan%2860%5C%C2%B0%29%3D%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B2%7D)
![tan(60\°)=\sqrt{3}](https://tex.z-dn.net/?f=tan%2860%5C%C2%B0%29%3D%5Csqrt%7B3%7D)
A percentage/ a percentile?
It has zero solutions because -5a+5a= 0, and 9 does not equal zero, so there are no solutions.
Answer:
s = 4.43
Step-by-step explanation:
Using formula for bigger circle
s =r∅
Where s is the Arc length, r is rdius and ∅ is theta(angle)
8.84=5∅
∅= 8.84/5
Angle = 1.77 radians
So both angles equal to 1.77 radians
Now again
Using formula
s = r∅
Where s is the Arc length, r is rdius and ∅ is theta(angle)
s = (2.5)(1.77)
s ≈ 4.43