Question

Select the correct comparison set a set b O A the typical value is greater is set a the spread is greater in set b

Answer 1

Answer:

(a)

Step-by-step explanation:

Given

See attachment for sets A and B

Required

The true statement about both sets

First, we calculate the typical values (mean) of set A and set B.

This is calculated as:

$Mean = \frac{\sum fx}{\sum f}$

For A:

$A= \frac{0*1+2*1+5*1+6*1+7*1}{1+1+1+1+1}$

$A= \frac{20}{5}$

$A =4$

For B:

$B = \frac{7 * 1 + 8 *1 + 9 * 2 + 10 * 1}{1+1+2+1}$

$B = \frac{43}{5}$

$B = 8.6$

Here, we can conclude that B has a larger typical value

Next calculate the spread (range) of sets A and B

This is calculated as:

$Range = Highest -Least$

For A:

$A = 7 - 0$

$A = 7$

For B

$B=10 - 7$

$B = 3$

Here, we can conclude that A has a larger spread.

Hence, (a) is true