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Lostsunrise [7]
3 years ago
6

A deck of cards is made up of 4 suits: clubs, diamonds, hearts, and spades.

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

i think the answer is c cuz theres 36 number cards

You might be interested in
A triangle has sides with lengths of 8 kilometers, 12 kilometers, and 13 kilometers. Is it a right triangle?
Andrej [43]

Answer:

no its not

Step-by-step explanation:

the sides make angles that are only obtuse and acute

6 0
3 years ago
HELP NEEDED!
SOVA2 [1]

Answer:

10000\pi

Step-by-step explanation:

The formula for circumference is given by 2\pi r. Setting this equal to the circumference in the problem, we can find the radius of the sphere:

2\pi r=100\pi, \\r=\frac{100\pi}{2\pi},\\r=50

Now we can use the formula for the surface area of a sphere:

Surface area of a sphere: A=4\pi r^2

Using r=50:

A=4\cdot \pi \cdot 50^2,\\A=4\cdot 2500\cdot \pi,\\A=\boxed{10000\pi}

5 0
3 years ago
Please help me I dont understand any of this. Ps it might take me a while for me to understand. :/
Tems11 [23]

How to clear an equation/solve for any given variable?

Lets say you have two identical cups of coffee, a and b.

You can say they're both equal. If you want to add a tablespoon of sugar to cup a, and you also want both cups to remain equal, you'll have to add the same tablespoon of sugar to cup b.

We use this fact, called conservation of an equality, to clear an equation (A.K.A solving for a variable)

Mathematically speaking,

<em>Cups </em>a <em>and </em>b<em> are equal</em>

a=b

<em>If you modify </em>a<em>, you'll have to modify </em>b <em>the same way</em>

\begin{gathered} a+3=b+3 \\ a-1=b-1 \\ a\times4=b\times4 \\ \frac{a}{5}=\frac{b}{5} \end{gathered}

Now, let's apply that logic to the equation we have.

We know cup of coffee a is

6y-1.5x

And cup b is

8

We also know both cups of coffee are equal, so

6y-1.5x=8

We're being asked to solve for y. In other words, we have to clear y from this expression.

Let's add our first tablespoon of sugar: adding 1.5x to both sides:

\begin{gathered} 6y-1.5x=8\rightarrow6y-1.5x+1.5x=8+1.5x \\ \rightarrow6y=8+1.5x \end{gathered}

See how the -1.5x canceled out? That's what we're looking for! We want y to be left alone in its side.

Now, let's divide both sides by 6 to cancel out the 6 from 6y:

\begin{gathered} 6y=8+1.5x\rightarrow\frac{6y}{6}=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8}{6}+\frac{1.5}{6}x \\ \rightarrow y=1.33+0.25x \end{gathered}

He have cleared y / solved the equation for y

<em>Let's try with another example</em>

<em />

e.g:

<em>Solve the following equation for </em>b

3b+9a+12=6

Solution: Let's substract 12 from both sides:

\begin{gathered} 3b+9a+12=6\rightarrow3b+9a+12-12=6-12 \\ \rightarrow3b+9a=-6 \end{gathered}

Then, let's substract 9a from both sides

\begin{gathered} 3b+9a=-6\rightarrow3b+9a-9a=-6-9a \\ \rightarrow3b=-6-9a \end{gathered}

Let's divide both sides by 3

\begin{gathered} 3b=-6-9a\rightarrow\frac{3b}{3}=-\frac{6}{3}-\frac{9a}{3} \\ \rightarrow b=-2-3a \end{gathered}

8 0
1 year ago
In each turn of a game you toss two coins. if 2 heads come up, you win 2 points and if 1 head comes up you win 1 point. if no he
Blizzard [7]

The expected value of the number of points for each turn is 0.25

<h3>What is expected value?</h3>

Expected value describes the long term average level of a random variable based on its probabilty distribution.

Now, Probability that 2 heads come up is

P(2 is H) = 1/4

Probability that 1 heads come up is

P(1 is H) = 2/4

⇒P(1 is H) = 1/2

Probability that no head will come up

P(no H's) = 1/4

Hence, the expected value for winning of 2points, 1point and  lose of3 points is given as-

Expected value = 2 * P(2 is H) + 1 * P(1 is H)  - 3 * P(no H's)

⇒Expected value = 2 * 1/4 + 1 * 1/2 - 3 * 1/4

= 0.5 + 0.5 - 0.75

⇒Expected value = 0.25

More about Expected value :

brainly.com/question/22715250

#SPJ1

3 0
1 year ago
What is the answer to this in standard form y+4=2/3(x+7)
Mnenie [13.5K]
Y=2/3x+2/3

I hope this helps!
3 0
4 years ago
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