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kow [346]
3 years ago
6

What is the range of the function shown in this table? х 3 4 5 6 y 4 4 2 5

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

Answer:

2,4,5

Step-by-step explanation:

Do not repeat numbers, u need to put them in order from least to greatest, and range is for the y

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Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?
Yuliya22 [10]
<span>–4(x + 3) ≤ –2 – 2x

>>.....-4x -12 </span>≤ -2 -2x

>>  -12 +2 ≤ +2x 

>> - 10 ≤ 2x

>> -5 ≤ x............>> x >= -5 

This answer is not represented in the pictures you attached

The line starts in x = -5 and goes up to infinity
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Solve 6x+89(9)^2<br> 3(2x+2403)<br> 3(2x+234)<br> 6x+7209<br> which one would it be
iogann1982 [59]

Answer:

It would be the last one 6x+7209

Step-by-step explanation:

because it will be simplify not factor by

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Coach Jamison wants to celebrate the final win of the school's baseball season with a trip to the local fast food place. The tea
PIT_PIT [208]
So we have 2 variables here: tacos and orders of nachos.

When we translate the paragraphs into equation: 28t + 27n = 114.80 \\ \\ 12t + 3n = 37.20

Now, in this situation we can make use the elimination method by converting 3n to -27n.

- 108t - 27n = - 334.8

Add both equations: 28t + 27n - 108t - 27n = 114.8 - 334.8 \\ \\ - 80t = - 220 \\ \\ t = 2.75

So we find that one taco costs $2.75.

We can plug this into any of the first two equations to find n: 12 \times 2.75 + 3n = 37.2 \\ \\ 33 + 3n = 37.2 \\ \\ 3n = 4.2 \\ \\ n = 1.4

So one order of nachos cost $1.40.
4 0
3 years ago
A bakery sold 16 apple pie on Saturday they sold 4 more apple pies on Sunday than they did on Saturday how many apple pies did t
lys-0071 [83]

Answer:

20 apple pies

Step-by-step explanation:

On Saturday they sold 16, while on Sunday they sold 4 more.

16+4 = 20.

20 apple pies.

4 0
3 years ago
The lifespan of a lion in a particular zoo are normally distributed. The average lion lives 12.5 years the. Standard deviation i
Anika [276]

Answer:

0.1585

Step-by-step explanation:

Solution:-

The lifespan of a lion in a particular zoo is normally distributed with average lion lives:

                    Mean u = 12.5 years

                    Standard deviation s = 2.4 years

We are to use the empirical rule ( 68-95-99.7% ) to estimate the probability of a lion living between 5.3 and 10.1.

- The empirical rule ( 68-95-99.7% ) states:

                     P ( u - s < X < u + s ) = 68%

                     P ( u - 2s < X < u + 2s ) = 95%

                     P ( u - 3s < X < u + 3s ) = 99.7%

- The test have the following number of standard deviations (s):

                 

                    u - s < X < u + s  = 12.5 - 2.4 < X < 12.5 + 2.4  = 10.1 < X < 14.9

                    u - 2s < X < u + 2s = 12.5 - 4.8 < X < 12.5 + 4.8  = 7.7 < X < 17.3

                    u - 3s < X < u + 3s = 12.5 - 7.2 < X < 12.5 + 7.2  = 5.3 < X < 19.7

Hence,

                   P ( 10.1 < X < 14.9 ) = 0.68

                   P ( 7.7 < X < 17.3 ) = 0.95

                   P ( 5.3 < X < 19.7 ) = 0.997

-  We need P ( X < 10.1 ) and P ( X < 5.3 ):

                  P ( X < 10.1 ) = [ 1 - P ( 10.1 < X < 14.9 ) ] / 2

                                      = [ 1 - 0.68 ] / 2

                                      = 0.16

                  P ( X < 5.3 ) = [ 1 - P ( 5.3 < X < 19.7 ) ] / 2

                                      = [ 1 - 0.997 ] / 2

                                      = 0.0015

Hence,

                 P ( 5.3 < X < 10.1 ) = P ( X < 10.1 ) - P ( X < 5.3 )

                                               = 0.16 - 0.0015

                                               = 0.1585

5 0
3 years ago
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