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vfiekz [6]
3 years ago
6

PLSSS HELP ASAP solve questions 1-5 please

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

#1. 4x^2 + 17 - 15 = 0

Use the roots given, and plug them in to a factored form. Then, foil! It can also be helpful to multiply the equation to get rid of decimals/fractions.

(x - 3/4)(x + 5) = 0

x^2 - 3/4x + 5x - 3 3/4 = 0

x^2 + 4.25 - 3.75 = 0 (multiply everything by 4)

4x^2 + 17 - 15 = 0

#2. y = 0, -4

Both 4y^2 and 16y contain a 4 in the coefficient and a y in the variables. Therefore, we can factor out a 4y from each.

4y(y + 4) = 0

Then, set both parts of the factored equation equal to 0.

4y = 0

y = 0

y + 4 = 0

y = -4

#3. a = 0, -3

Both 6a^5 and 18a^4 contain a 6 in the coefficient and an a in the variables. Therefore, we can factor out a 6a^4 from each.

6a^4(a + 3) = 0

Then, set both parts of the factored equation equal to 0.

6a^4 = 0

a = 0

a + 3 = 0

a = -3

#4. x = -8

We are looking for two terms that multiply to equal a * c, and add up to equal b. We know that 8 + 8 = 16, and 8 * 8 = 64. There are no negatives in this equation, therefore both signs in our factored form are positive.

(x + 8)(x + 8) = 0

x + 8 = 0

x = -8

#5. x = -8, 8

First, subtract 64 from both sides. The key word here is 'factoring.' If this was not present, there is a different way (which may be easier for some).

x^2 = 64

x^2 - 64 = 0

Next, use the difference of two squares property to factor (x - c)(x + c), and set the two binomials equal to 0.

(x - 8)(x + 8) = 0

x - 8 = 0

x = 8

x + 8 = 0

x = -8

Hope this helps!! :)

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( - 41) + ( - 40) \\  - 41 - 40 \\ 81

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Each side of the smaller square in the figure below is n inches long, and each side of the larger square is p inches longer than
lana66690 [7]

Answer:

2np + p²

Step-by-step explanation:

The general formula for the area of a square is A = s², where s = the length of one side of the square.  In the case of the smaller square the area would be: n x n = n².  Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'.  To find the area of the larger square, we have to take the length x length or (n +p)².

Using FOIL (forward, outside, inside, last):

(n + p)(n+p) = n² + 2np + p²

Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.

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3 years ago
Solve the quadratic equation by factoring. 9x^2+24x+20=4
const2013 [10]

D. -4/3

Let's solve your equation step-by-step.

9x2+24x+20=4

Step 1: Subtract 4 from both sides.

9x2+24x+20−4=4−4

9x2+24x+16=0

Step 2: Factor left side of equation.

(3x+4)(3x+4)=0

Step 3: Set factors equal to 0.

3x+4=0 or 3x+4=0

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Hope This helps

5 0
3 years ago
Match each scenario involving projectile motion with the equation that describes the height of the object at time t. Tiles h = -
olga55 [171]

Answer:

  1. h = -16t^2 + 73t + 5
  2. h = -16t^2 + 5
  3. h = -4.9t^2 + 73t + 1.5
  4. h = -4.9t^2 + 1.5

Step-by-step explanation:

The general equation we use for ballistic motion is ...

  h(t)=\frac{1}{2}gt^2+v_0t+h_0

where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.

The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.

_____

Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)

A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)

Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)

Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)

_____

<em>Additional comment on these scenarios</em>

The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for <em>vertical</em> motion, so we must assume the launches are <em>straight up</em> (or that the up-directed component of motion is 73 units/second).

4 0
3 years ago
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