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Firdavs [7]
3 years ago
15

Write an equation that is parallel to the line 2x - 3y = 9 and passes through the point (4, -1).

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer: y = \frac{2x}{3} - \frac{11}{3}

Step-by-step explanation:

Equation of the line given ;

2x - 3y = 9

To find the slope of the line we will make y the subject of formula , that is

3y = 2x - 9

y = \frac{2x}{3}-3

Therefore ; the slope = \frac{2}{3}

Two lines are said to be parallel if they have the same slope

This means that the slope of the second line = \frac{2}{3}

Using the formula y-y_{1}= m ( x - x_{1} ) to find the equation of the line , we have

y - (-1 ) = \frac{2}{3} (x - 4 )

y + 1 = \frac{2x}{3} -\frac{2}{3}(4)

y + 1 = \frac{2x}{3} - \frac{8}{3}

y = \frac{2x}{3}-  \frac{8}{3}  - 1

y = \frac{2x}{3} - \frac{11}{3}

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