I am pretty sure it is B) upper quartile but not 100% sure
Hope it helps! - Alyssa

Using the identity:

, we get:

There are two solutions to this equation:
1) 
Since the period of cosine is 2π, so 0 + 2π = 2π will also be a solution to the given equation
2)
Therefore, there are 3 solutions to the given trigonometric equation.
IT IS TWELVE............ 12
:If PQRS is a parallelogram with two adjacent congruent sides, then the quadrilateral yielded becomes a rhombus:
A rhombus is a quadrilateral that has the same properties as a parallelogram but all sides are congruent