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AlladinOne [14]
3 years ago
13

Study the solutions of the three equations on the right. Then, complete the statements below. There are two real solutions if th

e radicand is There is one real solution if the radicand is There are no real solutions if the radicand is 1. y = negative 16 x squared + 32 x minus 10. x = StartFraction negative 32 plus-or-minus StartRoot 384 EndRoot Over negative 32 EndFraction. 2. y = 4 x squared + 12 x + 9. x = StartFraction negative 12 plus-or-minus StartRoot 0 EndRoot Over 8 EndFraction. 3. y = 3x squared minus 5 x + 4. x = StartFraction 5 plus-or-minus StartRoot negative 23 EndRoot Over 6 EndFraction.
Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

There are two real solutions if the radicand is

✔ positive.

There is one real solution if the radicand is

✔ zero.

There are no real solutions if the radicand is

✔ negative.

Step-by-step explanation:

ON MY DOG KIDS DIS RIGHT

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