Answer:
The word problem is "How many $25 are there in $125?"
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Step-by-step explanation:
Given
Required
Write a word problem for the expression
We start by solving the given equation
Divide both sides by $25
This implies that there are 5, $25 in $125
<em>Hence; The word problem is "How many $25 are there in $125?"</em>
If this is correct the answer would be
y^2 + 0.1y + 0.0025
Answer:
b: -2y and 4y
Step-by-step explanation:
The answer is option B
-2y and 4y are like terms because they have the same algebraic alphabet at the back of their coefficients.
The sixth graders collected $250 of their $300 goal. The seventh graders collected $250 of thier $450 goal.
Sixth Graders:
$250 / $300
Reduce: $25 / $30 = 5/6
Seventh Graders:
$250 / $450
Reduce: $25 / $45 = 5/9
80 degrees. 145 = (4x+5) + (6x-10) = 10x-5... so 10x = 150, x = 15. LMN = 6x-10 = 6(15) - 10 = 80.
