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AlladinOne [14]
3 years ago
13

Study the solutions of the three equations on the right. Then, complete the statements below. There are two real solutions if th

e radicand is There is one real solution if the radicand is There are no real solutions if the radicand is 1. y = negative 16 x squared + 32 x minus 10. x = StartFraction negative 32 plus-or-minus StartRoot 384 EndRoot Over negative 32 EndFraction. 2. y = 4 x squared + 12 x + 9. x = StartFraction negative 12 plus-or-minus StartRoot 0 EndRoot Over 8 EndFraction. 3. y = 3x squared minus 5 x + 4. x = StartFraction 5 plus-or-minus StartRoot negative 23 EndRoot Over 6 EndFraction.
Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

There are two real solutions if the radicand is

✔ positive.

There is one real solution if the radicand is

✔ zero.

There are no real solutions if the radicand is

✔ negative.

Step-by-step explanation:

ON MY DOG KIDS DIS RIGHT

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Nataly [62]

Answer:

3 x (3 x - 5) (3 x + 5)

Step-by-step explanation:

Factor the following:

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Factor 3 x out of 27 x^3 - 75 x:

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9 x^2 - 25 = (3 x)^2 - 5^2:

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Factor the difference of two squares. (3 x)^2 - 5^2 = (3 x - 5) (3 x + 5):

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5 0
3 years ago
F(x)= √x-5. find f-2
rodikova [14]

For this case we have:

Be a function of the form y = f (x)

Where:

f (x) = \sqrt {x-5}

If we want to find f (-2), we substitute x = -2, then:

f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}

Since we have a negative root, the result will be given by complex numbers. By definition:

\sqrt {-1} = i

So:

f (-2) = \sqrt {7} i

Answer:

f (-2) = \sqrt {7} i


3 0
3 years ago
5000 rounded to the nearest 10 thousand
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6 0
3 years ago
A music store buys instruments and then sells them for 30% more than they paid.
seropon [69]

Answer:135.2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The forumla f = 3y yards y to feed f and f = (n/12) converts inches n to feet f. write a composition of functions that converts
Solnce55 [7]
Equating the two formulas for f, you have
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5 0
3 years ago
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