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AlladinOne [14]
3 years ago
13

Study the solutions of the three equations on the right. Then, complete the statements below. There are two real solutions if th

e radicand is There is one real solution if the radicand is There are no real solutions if the radicand is 1. y = negative 16 x squared + 32 x minus 10. x = StartFraction negative 32 plus-or-minus StartRoot 384 EndRoot Over negative 32 EndFraction. 2. y = 4 x squared + 12 x + 9. x = StartFraction negative 12 plus-or-minus StartRoot 0 EndRoot Over 8 EndFraction. 3. y = 3x squared minus 5 x + 4. x = StartFraction 5 plus-or-minus StartRoot negative 23 EndRoot Over 6 EndFraction.
Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

There are two real solutions if the radicand is

✔ positive.

There is one real solution if the radicand is

✔ zero.

There are no real solutions if the radicand is

✔ negative.

Step-by-step explanation:

ON MY DOG KIDS DIS RIGHT

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Round the number 15.39624 to 2 decimal places​
ivolga24 [154]

Answer:

answer is 15.40 because 9 is greater than 5 so 1 is carry over it .So answer is 15.40

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3 years ago
I need help..............
vovangra [49]

Answer:

  a_n=-3+7(n-1)

Step-by-step explanation:

The recursive rule tells you the initial term of the sequence is a1 = -3, and the common difference is d=7. (7 is the value added to one term to get the next term.)

Putting these values into the formula for the explicit rule gives ...

  an = a1 +d(n -1)

  an = -3 + 7(n -1)

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3 years ago
In the arithmetic sequence {13,6,−1,−8,…}, what is the common difference?
Charra [1.4K]

Answer:

-7

Step-by-step explanation:

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4 0
3 years ago
The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th
vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by P(t)=1.394(1.006)^t

To find the derivative you need to:

\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t

To find the population growing at the start of 2014 we say t = 0

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year

To find the population growing at the start of 2015 we say t = 1

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year

To convert billion to million you multiple by 1000

P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year

6 0
3 years ago
Oranges sell 8 for $1.84. Find the unit rate.
sweet-ann [11.9K]

Step-by-step explanation:

oranges sell 8 for 1.84$

so,

1 unit orange =\tt{\dfrac{1.84}{8}=0.23\$ } ⠀

3 0
3 years ago
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