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White raven [17]
3 years ago
15

Benny plant grew 16.8 centimeters this year. The plant grew the same amount each month. How much did the plant grow each month?

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

1.4 centimeters each month

Step-by-step explanation:

we know that there are 12 months in a year. if the plant grew 16.8 centimeters in one year, you would have to divide 16.8 by 12 so your equation would be:

16.8/12 = 1.4

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Which choice is equivalent to the expression below?
Mashutka [201]

Answer:

  • D. 4√5

Step-by-step explanation:

  • √20 - √5 + √45 =
  • 2√5 - √5 + 3√5 =
  • (2 - 1 + 3)√5 =
  • 4√5

Correct choice is D

5 0
3 years ago
Read 2 more answers
Y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′′(0) = 0
Snowcat [4.5K]

Answer:

y(t) =  3u₂(t) [ e^{-2t+4}  - e^{-5t + 10)} ] - 4u₅(t) [ e^{-2t+10)}  - e^{-5t + 25)} ]

Step-by-step explanation:

To find - y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′(0) = 0

Formula used -

L{δ(t − c)} = e^{-cs}

L{f''(t) = s²F(s) - sf(0) - f'(0)

L{f'(t) = sF(s) - f(0)

Solution -

By Applying Laplace transform, we get

L{y″+ 5y′ + 6y} = L{3δ(t − 2) − 4δ(t −5)}

⇒L{y''} + 5L{y'} + 6L{y} = 3L{δ(t − 2)}  − 4L{δ(t −5)}

⇒s²Y(s) - sy(0) - y'(0) + 5[sY(s) - y(0)] + 6Y(s) = 3e^{-2s} - 4e^{-5s}

⇒s²Y(s) - 0 - 0 + 5[sY(s) - 0] + 6Y(s) = 3e^{-2s} - 4e^{-5s}

⇒s²Y(s) + 5sY(s) + 6Y(s) = 3e^{-2s} - 4e^{-5s}

⇒[s² + 5s + 6] Y(s) = 3e^{-2s} - 4e^{-5s}

⇒[s² + 3s + 2s + 6] Y(s) = 3e^{-2s} - 4e^{-5s}

⇒[s(s + 3) + 2(s + 3)] Y(s) = 3e^{-2s} - 4e^{-5s}

⇒[(s + 2)(s + 3)] Y(s) = 3e^{-2s} - 4e^{-5s}

⇒Y(s) = \frac{3e^{-2s} }{(s + 2)(s + 3)} -  \frac{4e^{-5s} }{(s + 2)(s + 3)}

Now,

Let

\frac{1}{(s+2)(s+3)} = \frac{A}{s+2}  + \frac{B}{s+3} \\\frac{1}{(s+2)(s+3)} = \frac{A(s + 3) + B(s+2)}{(s+2)(s+3)}\\1 = As + 3A + Bs + 2B\\1 = (A+B)s + (3A + 2B)

By Comparing, we get

A + B = 0 and 3A + 2B = 1

⇒A = -B

and

3(-B) + 2B = 1

⇒-B = 1

⇒B = -1

So,

A = 1

∴ we get

\frac{1}{(s+2)(s+3)} = \frac{1}{s+2}  + \frac{-1}{s+3}

So,

Y(s) = 3e^{-2s}[ \frac{1}{(s + 2)} -    \frac{1}{(s + 3)}] - 4e^{-5s}[ \frac{1}{(s + 2)} -    \frac{1}{(s + 3)}]

⇒Y(s) = 3e^{-2s} \frac{1}{(s + 2)} -    3e^{-2s} \frac{1}{(s + 3)} - 4e^{-5s}\frac{1}{(s + 2)} + 4e^{-5s}\frac{1}{(s + 3)}

By applying inverse Laplace , we get

y(t) = 3u₂(t) [ e^{-2(t-2)}  - e^{-5(t - 2)} ] - 4u₅(t) [ e^{-2(t-5)}  - e^{-5(t - 5)} ]

⇒y(t) =  3u₂(t) [ e^{-2t+4}  - e^{-5t + 10)} ] - 4u₅(t) [ e^{-2t+10)}  - e^{-5t + 25)} ]

It is the required solution.

3 0
3 years ago
What is the slope and y intercept y+4= -4/7(x-5)
galben [10]

Answer:

The slope is -4/7 and the y-intercept is -8/7.

Step-by-step explanation:

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7y+28=-4x+20

7y=-4x-8

y=-4/7x-8/7

8 0
3 years ago
Lou has a part-time job in a restaurant. He earns $69.38 a day when he cooks and $56.63 a day when he busts his tables. Last wee
Stolb23 [73]

Answer:

$182.64

Step-by-step explanation:

$56.63x2 =$113.26

$113.26+$69.38

=$182.64

3 0
3 years ago
Least multiple of 5 and 25
melomori [17]

Answer:

  25

Step-by-step explanation:

25 is a multiple of 5, so is the least multiple of both 5 and 25.

8 0
3 years ago
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