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2 years ago

The table shows the prices for games in Bella's soccer league. Her parents and grandmother attended a

Mathematics

1 answer:

Kay [80]2 years ago

4 0

Answer: $55

Step-by-step explanation:

You have Bella’s parents and her grandmother going to the game= 3 non student tickets at $16 per ticket. 16x3=$48 for tickets and 1 car parked = $7. $48 + $7= $55

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Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the

lana66690 [7]

Answer:

$Width= 13 cm$

$length=30cm$

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

$Perimeter= 86 cm$

According to the statement:

$Length= 2*Width+4\\L=2W+4$

Perimeter of a rectangle= 2(Length+Width)

$86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm$

$Width= 13 cm$

$length=30cm$

6 0

2 years ago

(MATH) (6) ((PHOTO)) label is sq yd

Annette [7]

Answer:

20 sq yd

Step-by-step explanation:

To find the total amount of sq yd's of paint needed, you have to find the area.

The area of a triangle is: A = 1/2 bh

We know:

b = base = 8

h = height = 5

Plug in and solve:

A = 1/2 (8) (5)

A = 1/2 (40)

A = 20

5 0

2 years ago

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of

Rzqust [24]

Answer:

x=12

Step-by-step explanation:

For the given situation , a quantity x is added to $\frac{1}{4} x$ gives 15.

We can set up equation as

$x+\frac{1}{4}x=15$

Multiply each term by 4 on both sides to get rid the denominator.

It gives,

4 x+x=60

Now, combine like terms

5 x=60

Divide both sides by 5

x=12.

6 0

3 years ago

What is the range of the given function? {(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}

Novay_Z [31]

Range is the set of possible output values of a function. In this case, it’s (-9, -3, 0, 5, 7).

8 0

3 years ago