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kotegsom [21]
3 years ago
12

Cindy exercises 300 days a year. 3 out of five days she walks. The other days she rides her bike. How many days a year does Cind

y walk
Mathematics
1 answer:
tatiyna3 years ago
8 0
300/5=60
60*3=180 days
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3 years ago
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Step-by-step explanation:

4 0
3 years ago
In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

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3 0
3 years ago
HCF(320, x) = 20, LCM(320, x) = 2240, then x =
HACTEHA [7]

Answer:

  140

Step-by-step explanation:

When working HCF and LCM problems, I like to think in terms of this little diagram:

  (a [ b ) c]

It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.

__

Here, we're given ...

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  ab = 320

  abc = 2240

Then ...

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3 years ago
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Anna [14]

Answer:

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Step-by-step explanation:

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