<h2>
Answer:</h2>
Shown below
<h2>
Step-by-step explanation:</h2>
The most famous of the step functions is the greatest integer function, which is denoted by the parent function ![[x]](https://tex.z-dn.net/?f=%5Bx%5D)
.
So, this function is defined as:
![f(x)=[x] \ the \ greatest \ integer \ less \ than \ or \ equal \ to \ x](https://tex.z-dn.net/?f=f%28x%29%3D%5Bx%5D%20%5C%20the%20%5C%20greatest%20%5C%20integer%20%5C%20less%20%5C%20than%20%5C%20or%20%5C%20equal%20%5C%20to%20%5C%20x)
.
These are the characteristics of this function:
- The domain of the function is the set of all real numbers.
- The range of the function is the set of all integers.
- The graph has a
at 
and 
in the interval 
- The graph is constant between each pair of consecutive integers.
- The graph jumps vertically one unit at each integer value.
The function ![F(x)=[x]-2](https://tex.z-dn.net/?f=F%28x%29%3D%5Bx%5D-2)
represents the parent function shifted 2 units downward. Therefore, the correct option has been chosen in the attached figure.
Answer:
lessssssssssssssssssssssss
Answer:
41
Step-by-step explanation:
We can obtain the area of a triangle where two sides and an included angle is given by saying; 1/2 ab sinθ
where a and b are the given sides of the triangle and θ is the included angle.
From the formula for the area of the triangle;
Area of a triangle = 1/2 ac sin B
Area of the triangle = 1/2 * 9 * 11 * sin 124
Area of the triangle = 49.5 * sin 124
Area of the triangle = 41
The least common multiple of 96, 144, and 224 is 2016.
Hope this helps! :D
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
