I NEED HELP ASAP!!!!!

A brace for a shelf has the shape of a right triangle. its hypotenuse is 14 inches long and the two legs are equal in length. ho

maks197457 [2]

To answer this item, we make use of the equation derive from the Pythagorean theorem for right triangles which states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the two shorter sides. If we let x be the measure of both the shorter sides (we call this as legs), we have,
(14 in)² = (x²) + (x²)
Simplifying the equation,
196 in² = 2x²
Divide both sides of the equation by 2,
98 in² = x²
To get the value of x, we get the square root of both sides of the equation,
x = sqrt (98) = 7√2 inches

Hence, the measure of each leg of the right triangle is 7√2 inches or approximately 9.9 inches.

8 0

3 years ago

If a production line produces 50 mouse traps every 30 minutes over the course of a 10 hour work day with a half-hour break for l

kaheart [24]

The factory made 950 mousetraps

7 0

3 years ago

How do you change 24 2\5 into decimal?

seropon [69]

24 and 2/5=24+2/5
24=24

0.1=1/10
2/5=x/10
times both sides by 10
20/5=x
4=x
2/5=4/10=0.4

24 and 2/5=24+0.4=24.4

5 0

2 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

2 years ago

A rectangle an an area of 30 square meters anda has dimensionsperimeter of 34 meters. What are the of the rectangle

vazorg [7]

The sides of the rectangle are:
xy = 39
2x + 2y

Solve by simultaneous equation:
ysquared -17y + 30 = 0

Solution:
The sides are equal to 15 and 2

6 0

3 years ago