Answer: quotient is 2x^2 + 10x - 5

Solution:

The first polynomial is miswritten.

The right one is: 2x^3 + 4x^2 - 35x + 15.

So, the division is [2x^3 + 4x^2 - 35x + 15] / (x - 3)

The synthetic division uses the coeffcients and obviate the letters, but you have to be sure to respect the place of the coefficient.

So, in this case it is:

3 | 2      4    -35    15
   ---------------------------------
    2     10     - 5      0

So, the quotient is 2x^2 + 10x - 5, and the remainder is 0.

I like to show it in this other way:

   | 2     4     -35     15
   |
   |
3 |       +6    +30     -15
--------------------------------
    2     10    - 5         0

Of course they are the same coefficients and the answer continue being quotien 2x^2 + 10x - 5, remainder 0.

4 0

2 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

7 0

2 years ago