Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
i think {x,y} = {-5,-2}
Step-by-step explanation:
Answer:
440
Step-by-step explanation:
multiple of 220
220, 440
multiple of 88
88, 176, 264, 352, 440
Answer:
I'm gonna need to see the graph, sweetheart.
Answer:
slope = 3
Step-by-step explanation:
to find the slope you do (y2-y1)/(x2-x1)=m
so we can plug the points into this formula
(5,7) (2,-2)
x1 y1 x2 y2
-2-7/2-5=m
-9/-3=m
Simplifies to
3=m
