Answer:
D
you want to use the quadratic formula so you send the 6 over with the x² so you substact 6 on both sides and and and invisible 0x having your equation x²+0x-6 and substitute that equation into the quadratic formula
Answer:
Area of Triangle QRP = 3
Step-by-step explanation:
According to Question , We have a circle With Centre 'O' & Area 48 .
Area Of Circle = 48
= 48
r =
Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .
Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )
Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O
so Radius Of Circle With Centre P() =
Now We Have To Find Area Of Equilateral Triangle .
A =
A=
The Area Of PQR is = 3
For Diagram , Please Find In Attachment
Answer:
A. No, it does not pass the vertical-line test..
Step-by-step explanation:
A. is the correct answer, as functions cannot have the same x value correspond to different y values. For a function to be considered a function, it must always pass the vertical line test.
Just divide 402 by 8
402 is in the house 8 is on the outside
1) New Wilmington-> Mercer: 1.25in
Mercer -> Sharon: 1.5in
-> in total 2.75in
scale 1 in:12 mi
->in total scaled: 2.75*12 mi=24+9mi=33mi
2) New Wilmington-> Volant: 1.25in
Volant -> Sharon: 2in
-> in total 3.25in
scale 1in:12mi
->in total scaled: 3.25*12 mi=36+3mi=39mi
so the answer is B) 33 mi; 39 mi