Answer:
We have four functions:
For f(x) we have two points (-2,2) and (-1,-1)
we will use two point form which is:
![y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
So, on substituting the values we get:
![y-2=\frac{-1-2}{-1-(-2)}(x-(-2))](https://tex.z-dn.net/?f=y-2%3D%5Cfrac%7B-1-2%7D%7B-1-%28-2%29%7D%28x-%28-2%29%29)
![y-2=\frac{-3}{x+2}](https://tex.z-dn.net/?f=y-2%3D%5Cfrac%7B-3%7D%7Bx%2B2%7D)
![y=-3x-4](https://tex.z-dn.net/?f=y%3D-3x-4)
So, f(x)=-3x-4
We have g(x)=3x-4
Now, we will from h(x) we have two points let initial point on monday is (0,4) and tuesday (1,1) again use two point form we get:
![y-4=-3(x-0)](https://tex.z-dn.net/?f=y-4%3D-3%28x-0%29)
![\Rightarrow y=-3x+4](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D-3x%2B4)
So, h(x)= -3x+4
Now, we will form j(x) we have three points (2,10) , (-2,6) and (2,22)
We will use (-2,6) and (2,22) to find the function with two point form.
![y-6=\frac{22-6}{2+2}x+2)](https://tex.z-dn.net/?f=y-6%3D%5Cfrac%7B22-6%7D%7B2%2B2%7Dx%2B2%29)
![\Rightarrow y=4x+14](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D4x%2B14)
j(x)= 4x+14
To find the slope we will compare the given function with general equation which is y= mx +c; m is the slope
And to find y-intercept we will put x=0
f(x)=-3x-4
Slope is: -3
And y-intercept is: (0,-4)
g(x)=3x-4
Slope is: 3
And y-intercept is: (0,-4)
h(x)= -3x+4
Slope is: -3
And y-intercept is: (0,4)
j(x)= 4x+14
Slope is: 4
And y-intercept is: (0,14)