Well we know the arc two secant/(secant and tangent lines) intersecting on a point of a circle subtends will be twice of that the angle the two lines make themselves. So in this problem the tang. and sec. lines intersect on the circle so that means the arc they subtend is twice as angle 8. So it is 2 × ∠8 = 220° so ∠8 is 110°
Answer:
4(-6), 6(-4), 12(-2)
Step-by-step explanation:
-4(6) = -4 x 6 = -24
so
4(-6) = 4 x -6 = -24
6(-4) = 6 x -4 = -24
12(-2) = 12 x -2 = -24
The answer is w=5 how I got it was u add 10 to both sides than minus seven to both sides than u divide and u get w=5
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