Answer:
The given functions are
The sine function has a standard period of 
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is .
Now, the images of each function is the y-variable set values that defines each function.
So, the function has an image defined by the set ![[-3,5]](https://tex.z-dn.net/?f=%5B-3%2C5%5D)
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to .
About the second function , the image set is ![[-2,2]](https://tex.z-dn.net/?f=%5B-2%2C2%5D)
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Answer:
metric unit - a decimal unit of measurement of the metric system (based on meters and kilograms and seconds); "convert all the measurements to metric units"; "it is easier to work in metric". metric.
Step-by-step explanation:
C. i hope this is correct
Answer/Step-by-step explanation:
2x-5y=9
Add 5y to both sides of the equation.
2x=9+5y
Divide each term by 2 and simplify.
Divide each term in 2x=9+5y by 2
Cancel the common factor of 2.
Divide x by 1.
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3x+4y=2
Add 4y to both sides of the equation
3x=2+4y
Divide each term by 3 and simplify.
Divide each term in 3x=2+4y by 3.
Cancel the common factor of 3.
Divide x by 1.
Answer:
the 3 one is the correct answer
Step-by-step explanation:
