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nikitadnepr [17]
2 years ago
14

Find Side BC and round to the nearest tenth of a decimal

Mathematics
2 answers:
wel2 years ago
7 0

Answer:

17.0

Step-by-step explanation:

If you take the sin(39) or cos(51), it is equal to BC/27. Multiply by 27 on both sides to get 27cos(51) or 27sin(39)= x. Plug into the calculator, and voila.

saw5 [17]2 years ago
7 0
17.0 is your answer.
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Answer:

C.I =  0.7608   ≤ p ≤   0.8392

Step-by-step explanation:

Given that:

Let consider a  random sample n = 400 candidates where  320 residents indicated that they voted for Obama

probability \hat p = \dfrac{320}{400}

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Level of significance ∝ = 100 -95%

= 5%

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The objective is to  develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

=\hat p  \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }

where;

Z_{0.05/2} = Z_{0.025} = 1.960

SO;

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }

=0.8  \pm 1.960 \sqrt{4 \times 10^{-4}}

=0.8  \pm 1.960 \times 0.02}

=0.8  \pm 0.0392

= 0.8 - 0.0392     OR   0.8 + 0.0392  

= 0.7608    OR    0.8392

Thus; C.I =  0.7608   ≤ p ≤   0.8392

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