Find Side BC and round to the nearest tenth of a decimal
2 answers:
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Answer:
Step-by-step explanation:
Let the original fraction be
Then adding 1 to the numerator gives
=
( cross- multiply )
⇒ y = 5x + 5 → (1)
Subtracting 1 from the denominator gives
=
(cross- multiply )
y - 1 = 7x → (2)
Substitute y = 5x + 5 into (2)
5x + 5 - 1 = 7x ← subtract 5x from both sides
4 = 2x ⇒ x = 2
Substitute x = 2 into (1)
y = (5 × 2) + 5 = 10 + 5 = 15
Hence original fraction =
