2 years ago

Find Side BC and round to the nearest tenth of a decimal

Mathematics

2 answers:

wel2 years ago

7 0

Answer:

17.0

Step-by-step explanation:

If you take the sin(39) or cos(51), it is equal to BC/27. Multiply by 27 on both sides to get 27cos(51) or 27sin(39)= x. Plug into the calculator, and voila.

saw5 [17]2 years ago

7 0

17.0 is your answer.

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$\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}$

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$\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}$

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